$$\text{pOH} = \text{p}K_b + \log_{10}\left(\frac{[\text{Salt}]}{[\text{Base}]}\right)$$
Concept: Calculates the pOH of a basic buffer solution containing a weak base and its conjugate acid.
Notation:
- $$\text{pOH}$$ = Potential of hydroxide;
- $$\text{p}K_b$$ = $$-\log_{10}K_b$$
- $$[\text{Salt}]$$ = Molar concentration of salt;
- $$[\text{Base}]$$ = Molar concentration of weak base.