Quadrilateral - Areas and Properties

Very Important

If a quadrilateral has all its vertices on the circle and its opposite angles are supplementary (here x+y = 180°), then that quadrilateral is called a cyclic quadrilateral.

  • In a cyclic quadrilateral, the opposite angles are supplementary
  • Area of a cyclic quadrilateral is $$A$$ = $$\sqrt{(s-a)(s-b)(s-c)(s-d)} $$ where s=(a+b+c+d)/2
  • The exterior angle is equal to the opposite angle of its remote interior angle. (here ∠CBX = ∠ADC)
  • Area = 1/2 * One diagonal * Sum of perpendiculars drawn to the diagonal
  • Ptolemy's theorem states that the product of the diagonals equals the sum of the products of the opposite sides. AC*BD = AB*CD + AD*BC.

  • Rectangle: Area = l × b, Diagonal = $$\sqrt{(l² + b²)}$$.
  • Square: Area = a², Diagonal = a$$\sqrt{2}$$.
  • Rhombus: Side = $$\sqrt{((d₁/2)² + (d₂/2)²)}$$.
  • Median of a trapezium (mid-segment) = (sum of parallel sides)/2.
  • For a trapezium, Area = 1/2 * sum of parallel sides * distance between them.
  • For a parallelogram, Area = Base * Height = Product of two sides * sine of the included angle.
  • For a rhombus, Area = 1/2 * Product of diagonals.
  • The sum of the three sides of a quadrilateral must be greater than the fourth side.

Formula Video


Question 1

If a rhombus has area 12 sq cm and side length 5 cm, then the length, in cm, of its longer diagonal is

Question 2

The sides AB and CD of a trapezium ABCD are parallel, with AB being the smaller side. P is the midpoint of CD and ABPD is a parallelogram. If the difference between the areas of the parallelogram ABPD and the triangle BPC is 10 sq cm, then the area, in sq cm, of the trapezium ABCD is

Question 3

The cost of fencing a rectangular plot is ₹ 200 per ft along one side, and ₹ 100 per ft along the three other sides. If the area of the rectangular plot is 60000 sq. ft, then the lowest possible cost of fencing all four sides, in INR, is

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