Question 9

In what ratio must a mixture of 40% acid be mixed with that of 60% acid to get a mixture of 49% acid?

Solution

Let the ratio in which 40% acid be mixed with that of 60% acid = $$x:y$$

According to ques,

=> $$40x+60y=49(x+y)$$

=> $$40x+60y=49x+49y$$

=> $$49x-40x=60y-49y$$

=> $$9x=11y$$

=> $$\frac{x}{y}=\frac{11}{9}$$

$$\therefore$$ Required ratio = 11 : 9

=> Ans - (C)

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