Question 9
In what ratio must a mixture of 40% acid be mixed with that of 60% acid to get a mixture of 49% acid?
Solution
Let the ratio in which 40% acid be mixed with that of 60% acid = $$x:y$$
According to ques,
=> $$40x+60y=49(x+y)$$
=> $$40x+60y=49x+49y$$
=> $$49x-40x=60y-49y$$
=> $$9x=11y$$
=> $$\frac{x}{y}=\frac{11}{9}$$
$$\therefore$$ Required ratio = 11 : 9
=> Ans - (C)
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