In what ratio must a mixture of 40% acid be mixed with that of 60% acid to get a mixture of 49% acid?
Let the ratio in which 40% acid be mixed with that of 60% acid = $$x:y$$
According to ques,
=> $$40x+60y=49(x+y)$$
=> $$40x+60y=49x+49y$$
=> $$49x-40x=60y-49y$$
=> $$9x=11y$$
=> $$\frac{x}{y}=\frac{11}{9}$$
$$\therefore$$ Required ratio = 11Â : 9
=> Ans - (C)
Create a FREE account and get:
