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Question 8
Two identical circles intersect so that their centres, and the points at which they intersect, form a square of side 1 cm. The area in sq. cm of the portion that is common to the two circles is
Solution
We know that quad ambn is a square of side 1.
Area of the sector a-mqn is $$\frac{90}{360}* \pi *1*1$$ = $$\frac{\pi }{4}$$.
Area of square = 1*1 = 1
Area of common portion = 2 * Area of sector - Area of square
= 2 * $$\frac{\pi }{4}$$ - 1 = $$\frac{\pi }{2}$$ - 1
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