Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 8
Two identical circles intersect so that their centres, and the points at which they intersect, form a square of side 1 cm. The area in sq. cm of the portion that is common to the two circles is
Solution
We know that quad ambn is a square of side 1.
Area of the sector a-mqn is $$\frac{90}{360}* \pi *1*1$$ = $$\frac{\pi }{4}$$.
Area of square = 1*1 = 1
Area of common portion = 2 * Area of sector - Area of square
= 2 * $$\frac{\pi }{4}$$ - 1 = $$\frac{\pi }{2}$$ - 1
Video Solution
Create a FREE account and get:
- All Quant CAT complete Formulas and shortcuts PDF
- 35+ CAT previous year papers with video solutions PDF
- 5000+ Topic-wise Previous year CAT Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Averages, Ratio and Proportion QuestionsCAT Data Sufficiency QuestionsCAT Averages QuestionsCAT Number Systems QuestionsCAT Remainders Questions
CAT DILR Questions | LRDI Questions For CAT
CAT DI with connected data sets QuestionsCAT 2D & 3D LR QuestionsCAT Miscellaneous LR QuestionsCAT Charts QuestionsCAT Quant Based LR Questions
