A parallelogram ABCD has area 48 sqcm. If the length of CD is 8 cm and that of AD is s cm, then which one of the following is necessarily true?
We can see that area of parallelogram ABCD = 2*Area of triangle ACD
48 = 2*Area of triangle ACD
Area of triangle ACD = 24
We know that $$sin\theta$$ $$\leq$$ 1, Hence, we can say that AD $$\geq$$ 6
$$\Rightarrow$$ s $$\geq$$ 6