Use the following information: Prakash has to decide whether or not to test a batch of 1000 widgets before sending them to the buyer.
In case he decides to test, he has two options:
a) Use test I ;
b) Use test II.

Test I cost Rs. 2 per widget. However, the test is not perfect. It sends 20% of the bad ones to the buyer as good. Test II costs Rs. 3 per widget. It brings out all the bad ones. A defective widget identified before sending can be corrected at a cost of Rs. 25 per widget. All defective widgets are identified at the buyer's end and penalty of Rs. 50 per defective widget has to be paid by Prakash.

Question 68

If there are 120 defective widgets in the lot, Prakash:


When there are 120 widgets defective:

Using 1st test:
Cost of testing = $$1000 \times 2 = 2000$$
Cost of correcting 80% pieces = $$96 \times 25 = 2400$$
Cost of penalty on 20% pieces = $$24 \times 50 = 1200$$
Total cost = 5600

Using 2nd test:

Cost of testing = $$1000 \times 3 = 3000$$
Cost of correcting all 120 pieces = $$120 \times 25 = 3000$$
Total cost = 6000

Using no test:

Total cost = 120 x 50 = 6000

Hence, he should use 1st test only.

Create a FREE account and get:

  • All Quant CAT complete Formulas and shortcuts PDF
  • 35+ CAT previous year papers with video solutions PDF
  • 5000+ Topic-wise Previous year CAT Solved Questions for Free


Boost your Prep!

Download App