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Question 53
The radius of in-circle of a triangle is 4 cm and the perimeterof the triangle is 20 cm. What is the area of the triangle?
Solution
$$\text{Radius of incircle} = \dfrac{\text{Area of the triangle}}{\text{Half of perimeter}}$$
Let the area of the triangle be A sq.cm
Given, Radius of incircle = 4 cm
Perimeter of the triangle = 20 cm
Then, Half of perimeter = 10 cm
$$4 = \dfrac{A}{10}$$
=> $$A = 40 cm^2$$
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