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Question 54
A room is in the shape of cube and the length of the longest rod placed in it is $$12\sqrt{3}$$ m. The area of the floor is:
Solution
The length of the largest rod placed in a room of cube shape will be its diagonal.
Diagonal of a cube = $$\sqrt{3}a$$ m where a = side of the cube.
Then, $$\sqrt{3}a = 12\sqrt{3}$$
=> $$a = 12$$
Floor will be in the shape of a square.
Therefore, Area of the floor = $$12^2 = 144 m^2$$
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