Question 52
Two ships meet mid-ocean, and then, one ship goes south and the other ship goes west, both travelling at constant speeds. Two hours later, they are 60 km apart. If the speed of one of the ships is 6 km per hour more than the other one, then the speed, in km per hour, of the slower ship is
Solution
Let the speeds of two ships be 'x' and 'x+6' km per hour
Distance covered in 2 hours will be 2x and 2x+12
It is given,
$$\left(2x\right)^2+\left(2x+12\right)^2=60^2$$
$$\left(x\right)^2+\left(x+6\right)^2=30^2$$
$$2x^2+12x+36=900$$
$$x^2+6x+18=450$$
$$x^2+6x-432=0$$
Solving, we get x = 18
The speed of slower ship is 18 kmph
The answer is option C.
Video Solution
Create a FREE account and get:
- All Quant CAT complete Formulas and shortcuts PDF
- 35+ CAT previous papers with video solutions PDF
- 5000+ Topic-wise Previous year CAT Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Remainders QuestionsCAT Mensuration QuestionsCAT Time And Work QuestionsCAT Probability, Combinatorics QuestionsCAT Percentages Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Quant Based LR QuestionsCAT Table with Missing values QuestionsCAT Scheduling QuestionsCAT Data Interpretation Basics QuestionsCAT DI Miscellaneous Questions
