Question 46
A man starting at a point walks one km east, then two km north, then one km east, then one km north, then one km east and then one km north to arrive at the destination. What is the shortest distance from the starting point to the destination?
Solution
In the diagram, A is starting point and B is ending point.
Accordingly, AB = $$\sqrt{(3^2 + 4^2)} = 5$$
In the diagram, A is starting point and B is ending point.
Accordingly, AB = $$\sqrt{(3^2 + 4^2)} = 5$$
Create a FREE account and get:
- All Quant CAT complete Formulas and shortcuts PDF
- 35+ CAT previous papers with video solutions PDF
- 5000+ Topic-wise Previous year CAT Solved Questions for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Algebra QuestionsCAT Data Sufficiency QuestionsCAT Time, Distance and Work QuestionsCAT Number Systems QuestionsCAT Linear Equations Questions
CAT DILR Questions | LRDI Questions For CAT
CAT DI with connected data sets QuestionsCAT Routes And Networks QuestionsCAT Special Charts QuestionsCAT Table with Missing values QuestionsCAT Selection With Condition Questions
