CAT 1998 Question Paper Question 38

Question 38

Find the value of X in terms of ‘a’.

I. Arithmetic mean of X and Y is ’a’ while the geometric mean is also ‘a’.

II. Y X = R; X - Y = D.


Statement 1: a = (X+Y)/2 and $$a^2 = XY$$. Hence, $$a=(X+a^2/X)/2$$. Hence, we can re-arrange the equation to represent X in terms of a

Statement 2: There is no relation given between X and a. Hence, we cannot find value of X in terms of a.

Hence, the question can be answered by one statement alone and not the other.

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