CAT 1996 Question 29

Question 29

The figure shows the rectangle ABCD with a semicircle and a circle inscribed inside in it as shown. What is the ratio of the area of the circle to that of the semicircle?

Solution

Let the center be O and the point at which the semicircle intersects CD be P.

Let the radius of the semicircle be R and the circle be r.

OP = R and OC = R$$\sqrt{2}$$

OC - OT = CC' - TC'

$$R\sqrt{2} - R - 2r$$ = $$r\sqrt{2} - r$$

=> $$R\sqrt{2} - R$$ = $$r\sqrt{2} + r$$

=> r = $$\frac{(\sqrt{2}-1)R}{\sqrt{2}+1}$$

=> r = $$(\sqrt{2}-1)^2$$R

Ratio of areas will be $$r^2 : \frac{R^2}{2}$$ = $$2(\sqrt{2}-1)^4$$ : 1


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