Question 25

Triangle $$ABC$$ is similar to triangle $$PQR$$ and $$AB : PQ = 2 : 3. AD$$ is the median to the side $$BC$$ in triangle $$ABC$$ and $$PS$$ is the median to the side $$QR$$ in triangle $$PQR.$$ What is the value of $$(\frac{BD}{QS})^2$$?

Solution

In the case of similar triangles AB/PQ =AC/PR =BC/QR
AB/PQ=2/3
AB/PQ=BC/QR
AB/PQ=2BD/2QS
AB/PQ=BD/QS
BD/QS=2/3
$$(\frac{BD}{QS})^2$$=4/9


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App