Question 24
In the given figure, $$ABCD$$ is a square whose side is 4 cm. $$P$$ is a point on the side $$AD$$. What is the minimum value (in cm) of $$BP + CP?$$
Solution
In this case if P is the midpoint then we will have the distance BP+CP as minimum since in every other position it will be more than as the distance increases when we go either way of AD
Given CD=4 cm
DP=2 cm
CP=$$\sqrt{16+4}$$
=$$\sqrt{20}$$
=2$$\sqrt{5}$$
BP=2$$\sqrt{5}$$
CP+BP=4$$\sqrt{5}$$
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