TS ICET 23rd May 2019 Shift-1

given that the number of days for individual require are = 7,14 and 28 days respectively 

then the total work is LCM of all of them = 56 

each have individual efficiency  = 56\7 , 56\14, and 56\28 = 8 , 4 and 2 

so they together finish the work = 56\(8+4+2) = 4 days 

let the rectangular length l = 80 m. and width w = 60 m. 

then the area of the  rectangular length = 4800 sq. m. 

and radius of the quadrant  $$r_{1}$$,$$r_{2}$$,$$r_{3}$$ and $$r_{4}$$ will be respectively 10,12,14 and 16 m 

then area of all quadrant = $$\pi$$ $$\times$$ $$r_{1}^{2}$$ \4 +  $$\pi$$ $$\times$$ $$r_{2}^{2}$$\4 + $$\pi$$ $$\times$$ $$r_{3}^{2}$$\4 +$$\pi$$ $$\times$$ $$r_{4}^{2}$$\4

                                      =  $$\pi$$ $$\times$$ $$10^{2}$$ \4 + $$\pi$$ $$\times$$ $$12^{2}$$\4 + $$\pi$$ $$\times$$ $$14^{2}$$\4 +$$\pi$$ $$\times$$ $$16^{2}$$\4  

                                      =  $$\pi$$ \4 $$\times$$ (100 + 144 + 196 + 256)

                                      = 174   $$\pi$$  Answer

let the lenth l = 5.5 m. and  w = 3.75 m. 

then the area of the room = l$$\times$$w = 5.5$$\times$$3.75

                                                               = 20.625 sq. m. 

then the total cost of paving the floor = 20.625$$\times$$800 = 16500 Rs.  Answer

let the side of cube is = a

then wholesale total area = 6 $$r^{2}$$ 

given that wholesale total area = 384 sq. cms 

then 

6 $$a^{2}$$ = 384

  a = 8 

then we know that the volume of the cube = $$a^{3}$$ = 512 sq. cms  Aanswer 

we know that 

the volume of the cone is  =  1\3 $$\times$$ $$\pi$$ $$\times$$ r^2 $$\times$$ h    and 

 the volume of the cylinder is =   $$\pi$$ $$\times$$ r^2 $$\times$$ h  then 

   volume of the cone \ volume of the cylinder =  1\3 $$\times$$ $$\pi$$ $$\times$$ r^2 $$\times$$ h \ $$\pi$$ $$\times$$ r^2 $$\times$$ h 

    volume of the cone \ volume of the cylinder = 1\3   Answer

given that the perimeter of the semicircle = 396 cm 

we know that the perimeter of the semiicircle = (1 + $$\pi$$\2) $$\times{d}$$ 

equate both the value

  (1 + $$\pi$$\2) $$\times{d}$$ = 396 cm  put the value $$\pi$$ = 22\7

(1 + 22\14) $$\times{d}$$ = 396 

                                 d    = 154 cm  Answer    

let the radius of the circle is r then area = $$\pi$$ $$r^{2}$$ 

then in given in the question the new radius is = 1.1r 

then the new area  = $$\pi$$ $$(1.1r)^{2}$$

                             = 1.21$$\pi$$ $$r^{2}$$

then the % change in area = (1.21$$\pi$$ $$r^{2}$$ - $$\pi$$ $$r^{2}$$)\$$\pi$$ $$r^{2}$$ $$\times$$100

then the % change in area = 21%   Answer 

We know that if |a| = b then a = $$\pm$$b

|x - 3| = 2 

x = 2 $$\pm$$3

x = 5 and 11 here x = 5 , 1

and 

|x - 1| = 5 in that equation x = 6 and 4 both are lie 1< X < 5 so x = 1, 5 Answer