Question 101

Three workers can individually complete a work in 7. 14 and 28 days respectively. If all the three work together the number of days needed to complete the same work is

Solution

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given that the number of days for individual require are = 7,14 and 28 days respectively 

then the total work is LCM of all of them = 56 

each have individual efficiency  = 56\7 , 56\14, and 56\28 = 8 , 4 and 2 

so they together finish the work = 56\(8+4+2) = 4 days 

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