Of the two workers 4 and B. the worker 4 works twice as fast as B. If B works alone the work could be completed in 12 days. If both A and B work together the numberof days in which the work can be completed is
Solution
given that B to complete the work = 12 days
so A to finish the work = 12\2 = 6 days ( A is twice faster than B so he require half the time as compared to B)
SO together A and B can finish the work in = (6 $$\times$$ 12 )\(6+12) = 4 days Answer
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