\left\\{x \epsilon R \mid \mid x - 3 \mid < 2 \wedge \mid x - 1 \mid < 5 \right\\} =

Question 109

$$\left\{x \epsilon R \mid \mid x - 3 \mid < 2 \wedge \mid x - 1 \mid < 5 \right\} =$$

Solution

We know that if |a| = b then a = $$\pm$$b

|x - 3| = 2

x = 2 $$\pm$$3

x = 5 and 11 here x = 5 , 1

and

|x - 1| = 5 in that equation x = 6 and 4 both are lie 1< X < 5 so x = 1, 5 Answer

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