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The perimeter of a semi-circle is 396 cm. Thenits diameter (in cm) 1s:
given that the perimeter of the semicircle = 396 cm
we know that the perimeter of the semiicircle = (1 + $$\pi$$\2) $$\times{d}$$
equate both the value
(1 + $$\pi$$\2) $$\times{d}$$ = 396 cm put the value $$\pi$$ = 22\7
(1 + 22\14) $$\times{d}$$ = 396
d = 154 cm Answer
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