TS ICET 23rd May 2019 Shift-1

let the income of A = x Rs , B = y RS and C = 20000 Rs 

given that 

x $$\times$$5%} = y $$\times$$ 15%                                equation 1 

and 10% $$\times$$ = 20% $$\times$$ 20000                   equation 2 

solve eq 2 we get y = 40000 Rs 

put value of y in eq 1 we get x= 12000 Rs 

so the total income is =  120000 + 40000 + 20000 = 180000 Rs Answer 

Let us assume that cost price of one Book is Rs1

So, The Cost price of 20 Books is =  Rs 20

Then,

Selling price of 16 Books = cost price of 20 Books => Rs 20

Now,

SP>CP

Thus there will be profit

Profit = 20-16  => 4

Profit % = 4/16 × 100 =  25 % Answer 

let the cost price of the article is x Rs 

then 120% of x  = 1.2x 

and  125% of x  =  1.25 x 

then in  given in question  1.25x - 1.20x = 50 

                                          0.05x          = 50 

                                                       x     =  $$\frac{50}{5}$$ $$\times$$ 100 

                                                      x      = 1000 Rs   Answer 

A and B starting capital respectively 80000 Rs and 120000 Rs 

and total capital of A = 80000$$\times$$ 4 + 80000 $$\times$$ 8 = 320000 + 800000  =  11200000 

      total capital of B = 1200000$$\times$$ 4 + 1200000 $$\times$$ 8 = 480000 + 1120000 = 16000000

           then   A : B =  11200000 : 1600000 

                    A : B  =  112 : 160  = 7 : 10 

  given that    X = 68000\17 = 4000 

then the difference in the profit  = ( 10 - 7 ) $$\times$$ 4000 = 12000 Rs   Answer             

let the total profit is = x Rs 

then after the 10%  deducting the taxes the profits is  = 0.9x 

then the ratio of given profit in between A and B = 3 : 2 

then  in according to the question 

      0.9x $$\times$$ $$\frac{2}{5}$$ = 6480 

                                                   x  = 72 $$\times$$250 

                                                   x  = 18000 Rs  Answer  

given that 

pipes A and B can fill a tank in 6 hours and 8 hours respectively 

so the tank capacity is LCM of 6 and 8 = 24 

   efficiency of A is = 24\6 = 4 

   efficiency of B is = 24\8 = 3 

together they can fill in 1 hour = 7 

then in 1.5 hour is = 10.5 

then the remaining part is = 13.5 

so time require to A to fill that = 13.5\4  = 27\8 

so the total time is =  27\8 + 3\2 = $$4\frac{7}{8}$$   Answer 

in question given that in 6 hours the tank is fill = $$\frac{3}{7}th$$ 

so the time required to fill the full tank =  6\$$\frac{3}{7}$$ hour 

                                                            =  14 hour Answer 

person speed in first case in meter \second is = 72$$\times$$5\18 = 20 m\sec 

and given that in second case the person speed is = 25 m\sec

so the difference is = 25 - 20 = 5 m\sec  Answer 

let the distance to travel of the person is = x km 

then in given in the question $$\Rightarrow$$  x\3 = 10 

                                                                     x = 30 km 

    then the speed = ( distance \time ) = 30 \ 6 = 5 kmph  Answer 

given that B to complete the work = 12 days 

so A to finish the work = 12\2 = 6 days ( A is twice faster than B so he require half the time as compared to B) 

SO together A and B can finish the work in = (6 $$\times$$ 12 )\(6+12) = 4 days    Answer