Question 96

Two pipes A and B can fill a huge tank in 6 hours and 8 hours respectively. If both the pipes are opened simultaneously and the B is tumed off after $$1\frac{1}{2}$$ hours then the time required for the tank to be full (in hours) is

Solution

given that

pipes A and B can fill a tank in 6 hours and 8 hours respectively

so the tank capacity is LCM of 6 and 8 = 24

efficiency of A is = 24\6 = 4

efficiency of B is = 24\8 = 3

together they can fill in 1 hour = 7

then in 1.5 hour is = 10.5

then the remaining part is = 13.5

so time require to A to fill that = 13.5\4 = 27\8

so the total time is = 27\8 + 3\2 = $$4\frac{7}{8}$$ Answer

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