SNAP 2014 Question Paper

In the first pair of words, vowels are taken together and written down in the alphabetical order followed by the consonants in the same alphabetical order.

So, for BEGUM, the vowels are E and U. The consonants are B,G and M. When arranged alphabetically, it becomes EUBGM- option A.

The analogy could be understood as the first word of the given pair is an extreme form of the other. 

So, running is an extreme form of walking. And hence, C is our answer.

From the statements
The possibilities are :

or

From the above two possibilities 
we can say Either I or III and either II or IV follows

Let the no of shots be x. Then,

Shots fired by A =(5/8)x

Shots fired by B = (3/8)x

Killing shots by A = 1/3 of (5/8)x = (5/24)x

Shots missed by B = 1/2 of (3/8)x = (3/16)x

(3/16)x = 27 ⇒

x =144

Birds killed by A = (5/24)x = (5/24)*144 = 30

The hour hand and the minute hands will be opposite to each other when the angle between them= $$180^{\circ\ }$$.

At 9PM, angle between the two hands= 270$$^{\circ\ }$$

The minute hand covers 360$$^{\circ\ }$$ in 60 minutes. So, in 1 minute, it covers $$\ \frac{\ 360^{\circ\ }}{60}$$= 6$$^{\circ\ }$$

Similarly for the hour hand, it covers 360$$^{\circ\ }$$ in 12 hours or 720 minutes. 

.'. The hour hand covers $$\ \frac{\ 360^{\circ\ }}{720}$$= 0.5$$^{\circ\ }$$.

Using the concept of relative speed, since both the hands move in the same directions, the effective speed= (6-0.5)$$^{\circ\ }$$ =5.5 or $$\ \frac{\ 11}{2}$$ degrees per minute.

Effective distance to cover= $$270^{\circ}-180^{\circ\ }=\ 90^{\circ\ }$$

Therefore time taken= $$\ \frac{\ 90}{\ \frac{\ 11}{2}}=\ \ \frac{\ 180}{11}=\ 16\ \frac{\ 4}{11}$$ minutes after 9 PM. 

Option B is our answer.

P $$\times$$ Q means P is the son of Q.

Q-S Means Q is the wife of S.

So, Q and S are a couple, where S is the husband and Q is the wife. Also, P is their son. 

So, S is the father of P.

With the given information, we can draw the following venn diagram:

For minimum students to appear for the exam, we can maximise the part common to VA and DI.

We will get the following final venn diagram:

So, total students appearing= 80+10+5+10= 105

With the given information, we can draw the following Venn diagram:

Let the number of students who cleared the cut-off in exactly one, two and three subjects be a, b and c, respectively, and the number of students who cleared the cut-off in both VA and DI be y.

Thus, c = 40

a + 2b + 3c = 80 + 70 + 60 = 210

a + 2(5 + 10 + y) + 3(40) = 210

a + 2y = 210 - 120 - 30

a + 2y = 60

We have to find the minimum value of a.

'a' is at least 5 as the students in only QA = 5.

At a = 5, y = $$\frac{55}{2}$$. Since y needs to be an integer, a cannot be 5.

At a = 10, y = 25. But in this case, the total number of students in VA = 75. Thus, a cannot be 10.

At a = 20, y = 20. This case satisfies all the conditions.

Hence, the minimum number of students who did not clear cut off in exactly two subjects = Minimum number of students who cleared only one subject = 20.

The answer is option C.

Since 40 students cleared cut off in all the three subjects, while 50 students cleared cut off in VA and QA hence the number of students who cleared cut off in only VA and QA is 50-40 =10

5 students cleared cut off in only QA hence the number of students who cleared cut off in only DI and QA is 60-40-10-5=5

Let the number of students who cleared cut off in only DI and VA is x.

From the given condition, the ratio is 15/5 = 3:1

Since 40 students cleared cut off in all the three subjects, while 50 students cleared cut off in VA and QA hence the number of students who cleared cut off in only VA and QA is 50-40 =10

5 students cleared cut off in only QA hence the number of students who cleared cut off in only DI and QA is 60-40-10-5=5

Let the number of students who cleared cut off in only DI and VA is x.

number of students who didn’t clear cut off in at least two subjects = (35-x)+(20-x) + 5 + 10 = 70-2x

This is max when x=0

=> number of students who failed in exactly one subject = 10+5+x = 15