SNAP 2007 Question Paper

The author says, "Some of the questions that scholars ask seem to the world to be scarcely worth asking, let alone answering. They ask questions too minute and specialized for you and me to understand without years of explanation."

So the correct answer is option D.

The author says, "Children whose curiosity survives parental discipline are invited to join our university. Within the university, they go on asking their questions and trying to find the answers. In the eyes of a scholar, that is mainly what a university is for."

So the correct answer is option D.

The author says, "If he is a scientist, that the answer will in some obscure way make possible a new machine or weapon or gadget. He talks that way because he knows that the world understands and respects utility."

So the correct answer is option B.

Option A is the correct answer. The author compares the scientist to both a historian and a mountain climber. Like a mountain climber, the scientist seeks answers out of curiosity, not for practical reasons. Similarly, like a historian, the scientist's pursuit of knowledge is driven by a desire to understand, not necessarily by future consequences.

The author says, "All this does not mean that the answers which scholars find to their questions have no consequences. They may have enormous consequences but these seldom form the reason for asking the question or pursuing the answers. It is true that scholars can be put to work answering questions for the sake of the consequences as thousands are working now, for example, in search of a cure for cancer. But this is not the primary function of the scholar, for the consequences are usually subordinate to the satisfaction of curiosity."

So the correct answer is Option C.

Idle curiosity" in the passage refers to d) casual curiosity. The term is used by the world to dismiss curiosity as something trivial or lacking serious purpose, despite the fact that curious people are rarely idle. The author contrasts this dismissive label with the persistent, driven nature of scholarly inquiry, suggesting that "idle" implies a superficial or nonchalant interest rather than the deep engagement curiosity actually entails.

5) This shows determination, the determined mind to do something when the conditions are not favourable. 
6) This shows willingness
7) This shows persistence

There is only one option that satisfies all of the above hence option B is the answer. 

The correct passive form is

His job is done well by him.

Pray means to address a deity, saint, prophet or object of worship.

Prey means the animal hunted or caught for food.

Prying means offensively curious.

The author says, "Together they perform about 80 corneal regeneration procedures a year, making the L.V. Prasad Eye Institute, where they work, one of the most prolific facilities in the world using stem cells to regenerate tissues of any kind. The Sangwan-Vemuganti team uses stem cells found in the tissues of living adults, not ones derived from embryos."

Option A is directly negated from the statement above. 

Option B, while true, is not what Sangwan-Vemuganti's team is known for. (This is not something unique to them.)

Option C is explicitly negated in the passage through the lines "Teams all over the world are working with adult stem cells, trying to coax them to regrow cells in hearts, brains, livers and other organs, but progress is slow."

Option D is exactly why the procedure is popular: they derive stem cells from living beings. 

Therefore, Option D is the correct answer. 

From the line,"....stem cells by his colleague Geeta Vemuganti in patients with damaged eyes."

It's not just the patients who require cornea transplants or have damaged corneas, as stated in options A and B. It is carried on patients with any kid of damaged eyes. 

Hence, Option C is the correct answer. 

This is in reference to the lines, "Indians are well known for reverse engineering, meaning they can deduce how drugs are made in order to produce generic versions. "

This is captured in option A. 

Other options are not the entire reason (B and C) or are not mentioned in the passage in any form (D). 

Therefore, Option A is the correct answer. 

This can be inferred from the lines "Sangwan and Vemuganti, a pathologist, developed the technique on their own from reading papers and running experiments in the lab."

This is best captured in option C. 

Option A comes close, but there were no procedures to follow as such, but research papers to experiment with. 

Therefore, Option C is the correct answer. 

Platform is used in the sentence: " Vemuganti’s major innovation was developing a platform on which to grow corneas."

Generic is used in the sentence, "Indians are well known for reverse engineering, meaning they can deduce how drugs are made to produce generic versions."

Here, platform refers to a method of making or procedure; generic means common or without a brand. 

Option D captures the meaning of these two words most appropriately. 

Therefore, Option D is the correct answer. 

Synonym of subtle is insiduous.

My mother, who is from the village, is very superstitious.

The correct punctuation is commas around the phrase "who is from the village" because it is a non-essential clause providing additional information.

The first sentence is incorrect.

"Those are they" is grammatically correct because "they" is the subject complement and should be in the subjective case. "Those are them" is incorrect because "them" is in the objective case, which is not appropriate in this context.

From this line, the convention on bio-diversity (CBD) in its Article 16.5 specifically asserts that intellectual property rights must not be in conflict with conservation and sustainable use of bio-diversity, a provision that has been totally ignored by those who composed the TRIPs agreement, we can infer that option A is the answer.

From the first line of the passage we can conclude that option D is the right answer.

A total of 170 countries signed CBD and 130 signed both TRIP and CBD. So percentage = (130/170)*100 = 76.5%

The author says, "While in case of agriculture the higher yield of patented products induces the farmers to switch from a more varied production pattern, the resulting narrowing of genetic base makes the economy and society more vulnerable to plant disease and epidemics." So the correct answer is option B.

From the line, Under Article 65, the developed countries have been asked to change their laws within another five years, and the less developed countries within an additional five years. The least developed countries have been asked to make those changes by 2005 AD, we can infer that there is a differentiation between developed and under developed countries so the answer is option D.

"Equivocate" means using ambiguous language so as to conceal the truth or avoid committing oneself.

Thus, the answer is option D.

Option A should have been "Paraphernalia".

Option B should have been 'Programme".

Option C is correct.

Option D should have been "Berserk".

Hence, the answer is option C.

Sentences 1 and 2 have the same meaning where the speaker wishes to know whether checking took place at the airport.

In sentence 3, the speaker is wondering whether checking should have been done or not.

In sentence 4, the speaker wants checking to happen at the airport.

Hence, the answer is option B.

In Options A and C, ‘concerned’ precedes ‘authority’. Here, ‘concerned’  acts as an adjective. ‘Concerned authority’ means that the authority is troubled or worried. Whereas ‘authority concerned’ refers to the authority that is dealing with the issue. In the latter, ‘concerned’ acts as a past participle, modifying "authority" to mean the authority that is involved or relevant to the matter at hand. Hence, Options A and C are eliminated. In Option B, ‘report’ has been placed before ‘once’. ‘Once’ is an adverb of frequency. As per the grammar rule, adverbs of
frequency are put directly before the main verb. So, Option B can be
eliminated.

In Option D, "Concerned" in "authority concerned" acts as a past participle, modifying "authority" to mean the authority that is involved or relevant to the matter at hand.

Hence, Option D is correct.

In sentence 5, "after" is used to connect two clauses. Thus, it is used as a conjunction. Hence, 3 - 5 is a match.

Hence, the answer is option D.

In sentence 6, "after" is to describe a noun "effect. Thus, it is used as an adjective. Hence, 1 - 6 is a match.

In sentence 8, "after" is used to describe the verb "came". Thus, it is used as an adverb. Hence, 2 - 8 is a match.

Thus, 4 - 7 is the final match.

"Neophyte" refers to a person who is new to a particular subject.

"Veteran" refers to a person who has had long experience in a particular field. Thus, it is the opposite of the given word.

Hence, the answer is option C.

The word "lame" can be used in sentences 1 and 3.

The word "crippled" can be used in sentences 2 and 4.

Hence, a word can be used a maximum of two times.

Hence, the answer is option C.

A "Firefly" is an insect which emits light.

A "Fire engine" is the vehicle used by firemen to help extinguish fires.

A "Fire escape" is a special route made to escape from buildings in case of fires.

Hence, the answer is option C.

2 will be the first statement as it mentions what freedom is being talked about in (I).

3 will follow 2 as it states that the freedom mentioned in 2 comes with great responsibility.

1 will continue the topic by saying that many of us fail to honour the responsibility mentioned in 3.

4 will conclude the argument sequence as it starts the idea continued in (II).

Hence, the answer is option B.

The author describes the enterprise mentioned in the passage as "Vaatsalya is one among rapidly spreading ‘for profit’ social enterprises that serve the poor and make a profit."

Option A: The conversation focuses on 'for profit' social enterprises. 

Option B: The author would not consider profiting from poor people appropriate. 

Option C: While this is somewhat close, the idea of profit is missing, and the experimental basis adds uncertainty. 

Option D: This is exactly what the author would consider an appropriate business model, with work for social causes while also making some form of profit. 

Therefore, Option D is the correct answer. 

The businesses mentioned in options A, C and D are all "for profit" enterprises that work on social causes.
While B (acumen Fund) is a US-based social fund that invests in these enterprises, and not a social cause enterprise itself. 

Hence, the answer is option B.

In the last paragraph, the author says, "‘For profit’ entrepreneurs are obsessed with social and environmental impact in addition to the financial returns. Since they are answerable to the investors, they try expanding the business rapidly."

Let's look at each option indiviually:

Option A: The scope of social entrepreneurs is not limited to NRIs. 

Option B: Viewing social work as charity is something the author explicitly mentions he does not consider. 

Option C: This fits best with the description given by the author about the social 'for profit' entrepreneurs. 

Option D: Similar to option A, the idea is not limited to sympathetic investors. 

Therefore, Option C is the correct answer. 

"Malinger" means to pretend to be ill in order to escape duty or work.

"Wander" means to roam aimlessly.

"Laze" means to pass time in a lazy manner.

"Evade" means to avoid doing something.

"Argue" means to express your disagreement angrily.

Options A, B and C have a similar meaning to Malinger.

Hence, option D is the answer.

2 starts with Padre Rotton being a striking case.

1 follows up with the padre’s rhetoric about the English and mentions his Anglo-Indian cousins.

4 provides details about the specific cousins, including James Rotton and the sons of his cousin Felix Rotton.

3 concludes with the activities of these relatives fighting on the rebel side in Avadh.

Hence, the correct answer is 2 1 4 3

Option A is both semantically and grammatically correct.

Options B and D mean that the scooterist was crossing the road. Also, B is semantically incorrect.

A scooterist who is across the road cannot hit you. Thus, option C is semantically incorrect.

Hence, the answer is option A.

Segment B should have been "so that we would be on time".

Hence, the answer is option B.

Options A, B and C all mean a loud, unpleasant noise.

Option D means a pleasant sound.

Hence, the answer is option D.

"Caw" refers to the harsh cry of a crow or similar birds.

Similarly, "Bellow" refers to the harsh cry of cows or similar animals.

Hence, the answer is option D.

SI = $$\frac{PTR}{100}$$

Given SI = 7/25P when t=4

$$\frac{7}{25}P\ =\frac{4PR}{100}$$

=> R=7

Number of days in February = 28

Number of months having three days less than 31 i.e, 28 days = 1

$$\therefore\ $$Required probability = $$\frac{1}{12}$$

Hence, the correct answer is Option D

First person: For every 2 steps he takes, the escalator moves by 3 steps at the same time.
Hence, 5 steps are covered at a time.
This is repeated 24 times(120/5).
Hence, first person takes = 24 *2 = 48 steps
Second person: For every 3 steps he takes, the escalator moves by 5 steps at the same time.
Hence, 8 steps are covered at a time.
This is repeated for 15 times(120/8)
Hence, second person takes = 3 * 15 = 45 steps
Total number of steps = 48 + 45 = 93

When arranged in ascending order, we get the noontime temperatures as:

66, 69, 70, 75, 77, 78 and 78.

m= 75.

f= 78 (occurs twice)

a= $$\ \frac{\ \left(66+69+70+75+77+78+78\right)}{7}=\ \ \frac{\ 513}{7}=73.29$$

So, a<m<f. -Option B

Lets assume the park is an equilateral triangle with side '2x' units, => the side of the flower bed = 'x' units

Area of park = $$\frac{\sqrt{\ 3}}{4}\cdot\left(2x\right)^2$$ =$$\frac{\sqrt{\ 3}}{4}\cdot4x^2$$

Area of flower bed = $$\frac{\sqrt{\ 3}}{4}\cdot x^2$$ 

Area of path = area of park -  area of flower bed = $$\frac{\sqrt{\ 3}}{4}\cdot3x^2$$

Ratio of area of path to area of flower bed = $$\frac{\left(\frac{\sqrt{\ 3}}{4}\cdot3x^2\right)}{\frac{\sqrt{\ 3}}{4}x^2}$$ = 3:1

f(x) = 3-x , if x$$\le\ $$0

$$\therefore\ $$ f(-3) = 3-(-3) = 6

By the given information,

Total number of Year III student's name= 3*100= 300

Total number of Year II student's name= 2*150= 300

Total number of Year I student's name= 1*200= 200. 

Number of favourable outcomes= year III student's name= 300 

Total Sample space= total number of names= 300+300+200= 800.

Therefore, required probability= $$\ \frac{\ 300}{800}=\ \ \frac{\ 3}{8}$$- Option D

This can be solved easily by using allegations

$$p=\frac{\left(p1q1+p2q2\right)}{q1+q2}$$

Here p = M , p1=P , p2=N

                     q1=3 , q2=6

$$\ \therefore\ M=\frac{\left(3P+6N\right)}{3+6}$$

On solving 3M = P+2N

Cubes are a 3-D figure, and so, the intersection of two 3-D figure must be a 2-D figure. 

So, Cube cannot be the intersection of two cubes.

Let the number of overtime hours logged be x.

Let the number of accidents reported be A.

So, since the relationship between A and x is linear, we can write A= ax+c

Given, when x=1000, A=8.

So, 8= 1000a+ c--------------(1)

Again, when x= 400, A=5.

So, 5= 400a+ c ----------------(2)

Subtracting Eqn 2 from 1, we get,

600a= 3

=> a= 1/200. 

Now putting this value of a in Eqn 1, we find

8= $$\ \frac{\ 1000}{200}+c$$

=>c= 8-5=3.

So, when x=0,

A= c= 3- option B

Let total number of days=20x

Number of rainy days = 2x

Number of rainbow days = x

Number of non rainbow days= 19x

$$\therefore\ $$ Percentage of non rainbow days = $$\frac{19x}{20x}\ \cdot\ 100\ =95$$

Considering statement 1 alone,

Let the number of balls in bag III be x.

The number of balls in bag I becomes x+5.

And the rest, which is 10- (x+x+5)= 5-2x balls are with C.

We cannot find the value of x, so Statement 1 alone is not sufficient.

Considering statement 2 alone, 

Let the number of balls in bag I be 2a

Balls in bag II will be a and the rest, i.e 10-3a will be in bag 3.

Again, we cannot find the value of a in this case, and hence, Statement 2 alone is not sufficient.

Considering both the statements and using the number of balls with each one of them as found using statement 1, we get

$$5+a=2\left(5-2a\right)$$

=>5+a= 10-4a

=> 5a=5, or a=1.

So, balls in Bag I= 5+a=6

balls in Bag II= 5-2a=3

balls in Bag III= a= 5.

Therefore, both statement I and II are required.

Let the side of the square lake be of length x kms.

Using pythagorus theorem, we can find the length of the diagonal as $$\sqrt{x^2+x^2}=\sqrt{2x^2}= x\sqrt{2}$$

'.' Area of the square= 50 sq. kms,

$$x^2=50$$ or x= $$5\sqrt{\ 2}$$

Therefore length of the diagonal = $$5\sqrt{\ 2}\cdot\sqrt{\ 2}=5\cdot2=10$$ km

Let's assume $$x$$ to be product of $$a, a+1, a+2,$$ and $$a+3$$

Hence, $$x=a(a+1)(a+2)(a+3)$$

$$n=a(a+1)(a+2)(a+3)+1$$

$$n=a(a+3)(a+1)(a+2)+1$$

$$n=(a^2+3a)(a^2+3a+2)+1$$

Let's assume$$a^2+3=p$$

$$n=p(p+2)+1$$

$$n=p^2+2p+1$$

$$n=(p+1)^2$$

Hence, we can say that n is a perfect square. 

Hence, 3 is true and 2 is automatically false as perfect squares can't be prime. 

Product of any 4 consecutive integers is always even, as one of the numbers among the 4 consecutive integers will be even and any number multiplied by an even number is even. x is even, hence x+1 is odd. thus n is odd. 

Hence both 1 and 3 are true.

Number of vowels in word EXAMINATION =6

Number of consonants in word EXAMINATION =5

Number of ways in which 6 vowels can be arranged in 6 odd places=(6!)/2!*2!   (1)

Number of ways in which 5 consonants can be arranged in 5 even places = 5!/2!        (2)
Now total arrangements = (1)*(2)
=10,800

The 6th and the 16th child divide the circle into two halves as it is given that the 6th child is diametrically opposite the 16th child. 

When we consider one of the two halves, it will contain students numbered from 7 to 15, i.e a total of 9 children. 

Similarly, the other side must also have 9 children.

Now, including the two pairs of 9 children at each half along with child numbered 6 and 16, we have a total of 9+9+2= 20 children.

Let us assume the number of apples purchased by the man to be x.

Then, the number of oranges will be (40-x).

Let the price of each apple be Rs. y and that of an orange be Rs. z

It is given that, xy+ (40-x)z= 17.

=> xy+40z-xz=17 ---------------(1)

Now, if the number of apples and oranges are interchanged, the apples will be (40-x) and the oranges will be x.

Given, the new total cost will be Rs. 15

So, (40-x)y + xz=15

=>40y-xy +xz= 15 ---------------(2)

Adding eqns 1 and 2, we get,

xy+40z-xz+40y-xy+xz=15+17

=> 40(y+z)=32

=>y+z= $$\ \frac{\ 32}{40}=\ \frac{\ 4}{5}$$

Or, the cost of one apple and one orange, x+y= Rs.$$\frac{\ 4}{5}=\ 80\ paise$$

By looking into the option, we can see that we only need to check the divisibility of the given number by 3 and 11.

Divisibility test by 3 : The given number, 311311311311311311311 has seven 3s and fourteen 1s.

So, the sum of the digits in the number= (7*3)+(14*1)= 21+14=35.

Since, 35 is not divisible by 3, the given number is not divisible by 3.

Divisibility test by 11: The sum of digits at odd places= (1+3+1+1+3+1+1+3+1+1+3)= 19

The sum of digits at even places= Sum of all the digits- Sum of digits at odd places= 35-19= 16.

Since, the difference between the the sum of digits at odd places and the sum of digits at even places, i.e. 19-16 is not a multiple of 11.

So, the given number is also not divisible by 11.

Hence, option D

Let us assume that the investment made at bank A at 6% S.I. is Rs. x

Since, total investment= Rs. 9000, Investment made at bank B at 8% S.I.= Rs. (9000-x)

From bank A, interest earned= $$\ \frac{\ P.r.t}{100}$$, where P= Principal amount, r= rate of Interest and t= time period of investment in years.

So, Interest from bank A= $$\ \frac{\ x.6.3}{100}$$= $$\ \frac{\ 18x}{100}$$

From Bank B, Interest earned for 3 years= $$\ \frac{\ \left(9000-x\right).8.3}{100}=\ \frac{\ 216000-24x}{100}$$

Equating the sum of interests earned from both the banks to the value given i.e. 1800, we find,

1800=$$\ \frac{\ 216000-24x}{100}+\ \frac{\ 18x}{100}=\ \frac{\ 216000-6x}{100}$$

=>$$\ 1800\cdot100=\ \ 216000-6x$$

=> $$\ 6x=\ \ 216000-180000$$

=>x=$$\ x=\ \ \ \frac{\ 36000}{6}$$

.'. x= Rs. 6000- Option B

Let us assume that the length of each bogy is 1 unit, and the speed of both A and B be s units.

Initially, both A and B had 12 bogies, and ran in opposite direction.

So, using the concept of relative speed, the effective speed of the two trains taken together, when travelling in opposite direction adds up.

Effective distance covered = 12+12 units=24.

Effective speed= 2s units.

Now, using time= $$\ \frac{\ Dis\tan ce}{Speed}$$, we get 2 mins= $$\ \frac{\ 24}{2s}$$

=>120=$$\ \frac{\ 12}{s}$$

.'.s= $$\ \frac{\ 1}{10}$$

In the new scenario, length of B becomes 16 units.

So, Effective distance covered = 12+16 units=28 units.

Effective speed= 2s units.

New time= $$\ \frac{\ 28}{2s}=\ \frac{\ 14}{s}$$=140.

So, increase in time in the new case= 140-120 seconds= 20 Seconds- Option D.

Let us draw the diagram of the ladder against the wall as given in the question.

Let the length of the ladder be t metres.

We can find BC, i.e the distance of the ladder from the foot of the wall using Pythagorus theorem

$$\ BC^2=\ t^2-5^2$$.,

=>$$\ BC^2=\ t^2-25$$

=> BC=$$\ BC^{ }=\ \sqrt{\ t^2-25}$$

Now, when the ladder is slips 2 m away from the wall, the ladder lies on the ground completely. This can be depicted as:

Now, BC+ BC'= t 

=> $$\ \ \sqrt{\ t^2-25}+2=t$$

=> $$\ \ \sqrt{\ t^2-25}=t-2$$

Squaring both sides,

$$\ \ t^2-25=\left(t-2\right)^2$$

=> $$\ \ t^2-25=\left(t^2-4t+4\right)$$

=>$$4t=29.\ And\ so,\ t=7.25$$

In the year 2003, Wheat: Rice=1.2 and it is given that Rice production= 4 lac tons.

Let the wheat production during 2003 be x.

So, $$\ \frac{\ x}{4}=\ \frac{\ 1.2}{1}$$

=> x= 4.8 lac tons

The number of years in which ratio of wheat production to rice production is greater than 1 will be the years where wheat production was greater than the rice production.
So number of years = 3

The years are 2002-2003, 2003-2004. and 2005-2006

Given Rice production in 2001 is 3 lac tons

Wheat Production during 2001 is 0.45*3 = 1.35 lac tons

So, total grains produced is 3+1.35 = 4.35 lac tons

Hence, the additional grains to be imported is 5-4.35 = 0.65 lac tons

Considering statement 1 alone, we can make a table as follow:

We get S-1220=P and S'-1400=1.32P

Since there are 3 variables, S, S' and P, we cannot get the values of the variable using the two equations alone. 

So, Statement 1 alone is not sufficient.

Using statement 2, 1.32P= 4300

=> P= 4300/1.32. But again, two variables, S and S' are unknown.

So, So, Statement 1 alone is not sufficient.

When we use both the given statements, we will have 

S-1220=4300/1.32 and 

S'-1400=4300.

Using these two equations, we can find S and S' respectively and hence answer the question asked.

Therefore, both statements are necessary to answer the question.

At t=0, speed was 40 kmph

At t=180, speed becomes 70 kmph

Therefore, increase in speed= $$\ \frac{\ 70-40}{40}.100=\ \frac{\ 30}{40}.100=75\%\ \ \ $$

Each of the options given assumes the speed of the train to vary linearly wrt time.

So, let us assume the speed of the train at time t be given by 40+ at, because at t=0, the speed was already 40 kmph.

When we put x=30, we get,

45= 40+ 30a

=> 5= 30a Or, a= $$\ \frac{\ 1}{6}\ \ \ $$

So, Speed= 40+ $$\ \frac{\ t}{6}\ \ \ $$

We will check again to verify the results. 

When t=60, Speed= 40+ $$\ \frac{\ 60}{6}\ \ \ $$= 50 kmph, which matches with the value given in the table.

So, Option D is correct

$$2\ \frac{\ 1}{2}\ $$ hours after the beginning of the time period means 120 +$$\left(2\ \cdot60\right)+\left(\frac{\ 1}{2}\cdot60\right)=\ 120+30=150\ \ \ $$ minutes.

From the table, we can infer that after 150 minutes, Speed of the train was 65 km/hour

Understanding the premise of the question, we can infer that the price of the laptop when taken individually is, let's say x and that of the printer is y. 

But, when taken together under the bundle offer, the price is lesser than (x+y), because of the discount given, let's say a%.

Statement 1 gives us the discounted price of the printer and laptop taken together, i.e. $$\ \left(x+y\right)\left(1-\ \frac{\ a}{100}\right)$$

We have three variables and cannot solve this equation.

Statement 2 gives us the value of x. But still, two variables, a and y are unknown.

Even if we use both the statements together, we will have 2 variables and only 1 equation.

Therefore, both statements are insufficient to find the value of y.

Considering statement X,

Percentage increase for Managerial candidates= $$\ \frac{\ \left(45292-19236\right)}{19236}\cdot100=\ \ \frac{\ 26056}{19236}\cdot100=135.45\%$$

Percentage increase in Technical candidates= $$\ \frac{\ \left(63298-61205\right)}{61205}\cdot100=3.3\%$$

Therefore statement X is true.

Considering statement Y,

Total registrations in 2004= 61205+19236= 80441.

Total registrations in 2005= 63298+45292= 108690.

So, growth in the overall number of registrations= $$\ \frac{\ \left(108690-80441\right)}{80441}\cdot100=35.11\%$$, which is greater than 25%.

So, both statement X and Y are true.

Statement X:

Percentage of drop-outs for Managerial category in 2004 = $$\ \frac{\ 19236\ -\ 15389}{19236}\times\ 100\ \approx\ 20\%$$

Percentage of drop-outs for Managerial category in 2005 = $$\ \frac{\ 45292\ -\ 40763}{45292}\times\ 100\ \approx\ 10\%$$

Therefore, percentage of drop-outs from 2004 to 2005 has decreased. Statement X is true.

Statement Y:

Percentage of drop-outs for Managerial category in 2005 = $$\ \frac{\ 45292\ -\ 40763}{45292}\times\ 100\ \approx\ 10\%$$

Percentage of drop-outs for Technical category in 2005 = $$\ \frac{\ 63298\ -\ 60133}{63298}\times\ 100\ \approx\ 5\%$$

Percentage of drop-out is lower for Technical category.

Statement Y is false

Answer is option A.

Evaluating statement X,

In the year 2005, In Managerial category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 399}{40763}=0.00978$$

In the year 2005, In Technical category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 637}{60133}=0.0106$$

So, statement X is false.

Evaluating statement Y,

In the year 2005, In Managerial category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 399}{40763}=0.00978$$

In the year 2004, In Managerial category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 138}{15389}=0.00896$$

So, statement Y is True. Hence, Option B.

Let's evaluate statement X first.

For technical jobs in 2004, the number of candidates offered jobs as a proportion of the number of CV’s posted=$$\ \frac{\ 181}{59981}=0.00301$$

For Managerial jobs in 2004, the number of candidates offered jobs as a proportion of the number of CV’s posted=$$\ \frac{\ 48}{15389}=0.00312$$

So, statement X is false.

Evaluating Y,

In technical category in 2004, the number of candidates offered jobs as a proportion of the candidates shortlisted=$$\ \frac{\ 181}{684}=0.2646$$

In Managerial category in 2004, the number of candidates offered jobs as a proportion of the candidates shortlisted=$$\ \frac{\ 48}{138}=0.3478$$

So, statement Y is also false.

Hence, option D.

We will go by the options to check each one of them

Option A says SIFY on BSE.

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 247-232}{232}\cdot100\%=\ \ \frac{\ 15}{232}\cdot100\%=6.465\%$$

Option B says INFY on NQE.

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 10.5-9.5}{9.5}\cdot100\%=\ \ \frac{\ 1}{9.5}\cdot100\%=10.52\%$$

Option C says Wipro on NQE.

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 6.5-5.5}{5.5}\cdot100\%=\ \ \frac{\ 1}{5.5}\cdot100\%=18.18\%$$

Option D says TCS on NQE

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 40-40.5}{40.5}\cdot100\%=\ \ \frac{\ -0.5}{40.5}\cdot100\%=-1.23\%$$

So, Option C shows the highest increase.

First we convert the currency of Kya Kya into Rs. by multiplying the values to 11 and we can get the following table:

In SIFY, profit made by him= $$\ \frac{\ 232-231}{231}\cdot100\%=0.43\%$$

In INFY, profit made= $$\ \frac{\ 105-104.5}{104.5}\cdot100\%=0.47\%$$

In WIPRO, profit made= $$\ \frac{\ 60.5-60}{60}\cdot100\%=0.83\%$$

In TCS, Profit made= $$\ \frac{\ 450-445.5}{445.5}\cdot100\%=1.01\%$$

Therefore, max profit is made in TCS share

Given, total shares of SIFY= 1000000

Shares purchased by SATYAM= 15% of 1000000= 150000.

Now, 50% of the shares were purchased at BSE's opening price i.e. Rs. 232 and 50% of the shares were purchased at BSE's closing price, Rs. 247.

So, total amount paid by SATYAM= 75000*(232)+ 75000(247)= Rs. 75000(479)= Rs. 35925000 which is close to Rs. 36 millions.

Average Salary in Administration = $$\ \frac{\ Total\ Salary\ }{Total\ number\ of\ People}$$

Total number of people on Administration = $$22\%\ of\ 18,000\ =\ 3,960$$

Hence $$12,000\ =\ \frac{\ Total\ Salary}{3,960}$$

Total Salary = $$12,000\times\ 3960\ =\ 47520000$$ = $$4.7\ crores$$

No of the employees in Sales & Marketing in 2005 = $$18\%\ of\ 18,000\ =\ 3240$$

No of the employees in Sales & Marketing in 2006 = $$20\%\ of\ 20,000\ =\ 4000$$

Percent Increase = $$\ \frac{\ 4000-3240}{3240}\times\ 100\%\ =\ 23.45\%$$

From above chart we can get the following table.

Variation of A = |4800-3960| = 840

Variation of B = |5200-4140 | = 1060

Variation of C = |4000-3240 | = 760

Variation of D = | 4000 - 5220 | = 1220

Variation of E = |2000-1440| =560

D has max variation

From the above charts, the following table can be made.

Let $$N$$ be the number of people who joined in 2006 in Operations department, then 

$$\ 4140-300+N\ =5200$$

$$N\ =1360$$

It is given that the labels are wrong.

For the Chest labelled "Gold or Silver": It should not have either Gold or Silver. Hence it has Bronze coins

For the Silver labelled chest. It can't have silver and broze is in other chest. Hence it has Gold Coins

Thus Gold labelled chest will have Silver coins.

We need not open any chest to determine the labels

Let $$x$$ minutes be the required time.

then 12 noon - 10:27 am = $$x$$

         $$x$$ = 1 hour 33 minutes = 93 minutes

In this question, it is given that Miss Harsha has been allotted Room 5 and she requires her neighbor to be non-smokers. This can be represented as follows

This implies Room 1, 2 and 3 have to be occupied by smokers as there are 3 smokers.

Further, it is given that Mr. Minhas (smoker) and Mr. Brar (non-smoker) need an adjacent office as they consult with each other. The only way possible is when Mr. Minhas gets room 3 and Mr. Brar gets room 4. This will lead to the allocation of Room 6 to Ms. Ruby as she the only non-smoker left.

Updated allocation looks like

Room 1 and 2 will be given to Mr. Dongre and Mr. Tanjore. Preferable location for Mr. Dongre will be Room 1 as he requires silence.

We see the ideal candidate to be furthest from Mr.Brar is Mr. Dongre

In this question, it is given that Miss Harsha has been allotted Room 5 and she requires her neighbor to be non-smokers. This can be represented as follows

This implies Room 1, 2 and 3 have to be occupied by smokers as there are 3 smokers.

In this question, it is given that Miss Harsha has been allotted Room 5 and she requires her neighbor to be non-smokers. This can be represented as follows

This implies Room 1, 2 and 3 have to be occupied by smokers as there are 3 smokers.

Further, it is given that Mr. Minhas (smoker) and Mr. Brar (non-smoker) need an adjacent office as they consult with each other. The only way possible is when Mr. Minhas gets room 3 and Mr. Brar gets room 4. This will lead to the allocation of Room 6 to Ms. Ruby as she the only non-smoker left. 

Updated allocation looks like

Room 1 and 2 will be given to Mr. Dongre and Mr. Tanjore. Preferable location for Mr. Dongre will be Room 1 as he requires silence.

A) If Mr. Dongre quits smoking it will not impact anyone

B) If Harsha has a noisy telephone installed in her office, Mr. Dongre who prefers silence would still be farthest from the noise hence he will not request for change

C) Since it is assumed that all the employees maintain an atmosphere of silence, the current allocation will not impact her 

D) If Mr. Tanjore takes up the role of Miss Ruby which requires talking on the phone. It will impact Mr. Dongre as he prefers silence in his office and he'll apply for change of rooms

Option D is correct

Since Shankar and Jwala will not work together and they have stated the same for their consent

Possible selection can be one of following 

i) Not take Jwala or Shankar

ii) Take only Jwala and leave Shankar

iii) Take only Shankar and leave Jwala

Option D captures the sense hence it is correct

Withdrawals and the Balance are 2 separate things. 

Imagine if the customer withdraws Rs.1 100 times. In this case sum of withdrawals will be still 100 but sum of balance = $$\left(99+98+...+1\right)\ne\ 100$$

Two totals need not be equal

In the given pattern, each row and column's figure have 2,3 and 4 legs. Therefore the missing figure should have 2 legs. This eliminates options 1,3 and 6.

Only one of the figures in each row/column has crooked "L" shaped legs. Hence Option 2 is also eliminated.

Each row and column should have one each of the following head

Thus option 5 satisfies all the criteria

The 1st figure in the analogy has 1 side less than the 2nd figure.

=> Since a rectangle has 4 sides, the answer should have 5 sides.

=> Option-C.

The Black Shade in the Big box is moving in the clockwise direction. Option D depicts the correct pattern

It is given that

i) Current MD remembers that he earned the most(70,000)

ii) Biswajit and Dhruv did not start on 50,000

iii) Chinmay does not remember what he started on. ( It implies Chinmay was not earning 70,000). The following things are known

We know that Biswajit's profession is Lawyer and Dhruv is an Engineer. From above table we observe that Chinmay is not MD. Thus Arvind is the MD and Chinmay is Doctor

Since neither Biswajit nor Dhruv started their salary at 50,000, Chinmay starting salary was 50,000

Given Arvind's Salary$$>$$ Biswajit's Salary and Doctor's Salary $$>$$ Dhruv's Salary. We obtain the following

Chinmay's Profession is Doctor

It is given that

i) Current MD remembers that he earned the most(70,000)

ii) Biswajit and Dhruv did not start on 50,000

iii) Chinmay does not remember what he started on. ( It implies Chinmay was not earning 70,000). The following things are known

We know that Biswajit's profession is Lawyer and Dhruv is an Engineer. From above table we observe that Chinmay is not MD. Thus Arvind is the MD and Chinmay is Doctor

Since neither Biswajit nor Dhruv started their salary at 50,000, Chinmay starting salary was 50,000

Given Arvind's Salary$$>$$ Biswajit's Salary and Doctor's Salary $$>$$ Dhruv's Salary. We obtain the following

The lawyer's starting salary was Rs 60,000

It is given that 

i) Current MD remembers that he earned the most(70,000)

ii) Biswajit and Dhruv did not start on 50,000

iii) Chinmay does not remember what he started on. ( It implies Chinmay was not earning 70,000). The following things are known

We know that Biswajit's profession is Lawyer and Dhruv is an Engineer. From above table we observe that Chinmay is not MD. Thus Arvind is the MD and Chinmay is Doctor

Since neither Biswajit nor Dhruv started their salary at 50,000, Chinmay starting salary was 50,000

Given Arvind's Salary$$>$$ Biswajit's Salary and Doctor's Salary $$>$$ Dhruv's Salary. We obtain the following

Arvind received the highest salary

For the man to take $$12^{th}$$ time rest he has to work for $$\left(12\times\ 8\right)=96$$ days and have rest for 11 days

Total days lapsed will be 96+11 = 107 and hence the $$12^{th}$$ rest day is $$108^{th}$$ day.

Day 1 is monday. After this Day 8 will be Monday. In general $$\left(7k+1\right)^{th}$$ day is Monday

Therefore $$106^{th}$$ day is Monday. $$108^{th}$$ day or $$12^{th}$$ rest day will be Wednesday

If we rotate the images we find ( 1,4,5 and 6 ) to be same figure and (2,3 and 7) to be the same figure.

Odd one out is (2,3 and 7)

It is given that there are 3 racers. Hence the rank given will be 1,2 and 3

Let us assume the first statement of Babloo is true, then the second will be false(Hence Waman is not in $$2^{nd}$$ place). Based on this the ranking will be as follows

But this will imply that both of Bunty's statement is false which is not allowed. 

Therefore the first statement of Babloee is False and the second Statement is true. Ranking based on this will be 

In this, we see that one statement of Bunty is true and the other one is false. Hence this is the correct ranking

Following are the possible routes

I) P-1-4-Q

II)P-1-5-Q

III)P-2-4-Q

IV)P-2-5-Q

V)P-3-4-Q

Total 5 routes are possible

On arranging words from Option B we get "SCANTY"

On arranging words from Option C we get "ASCENT"

On arranging words from Option D we get "SACHET"

No meaningful word is obtained by rearranging word in Option A

Let the average of the number of each row and column be integer denoted by $$x$$

Then the sum of numbers in Row 1 = $$4x$$.

Similarly for row 2 and row 3 the sum will be $$4x$$ each. Hence the sum of all the numbers in the table is $$12x$$.

Let $$N$$ be the number only number that is left out of the table.

Then, (1+2+3+4+5+7+9+10+11+12+13+14+15 -N) = $$12x$$ 

$$106-N\ =\ 12x$$

Since $$x$$ is integer then $$Remainder\left(\ \frac{\ 106-N}{12}\right)=0$$

$$Remainder\left(\ \frac{\ 10-N}{12}\right)=0$$

Hence N has to be 10 which is left out. And average of each row and column will be $$\ \frac{\ 106-10}{12}=\ \frac{\ 96}{12}=8$$

Upon solving the table will look as follows

In the patter we observe $$\ \frac{product\ of\ number\ in\ traigle\ }{product\ of\ number\ in\ sqaure\ and\ circle}\ =\ \ \frac{\ 6\times\ 8}{12\times\ 8}=\ \frac{\ 5\times\ 6}{6\times\ 10}=\ \frac{\ 1}{2}$$

Let the missing number be $$N$$

$$\ \frac{\ 3\times\ 12}{4\times\ N}=\ \frac{\ 1}{2}$$

$$N=18$$

It is observed that B onward the alphabets are changing position in sets of 4. Which can be observed as

letter "W" is placed below

Since there are Grandparents(Represented by A&B)  and Grand Children there will be 3 level Family Tree. 

Since there is one Daughter-in-law, its possible when they have a son(C). Then Daughter in Law (D). Also they have 3 grandchildren(E,F and G). It can be represented in the family tree in the following manner

Furthermore, there are 2 sisters and 1 brother. It is possible when one of the grandchildren is Male.

The above family tree satisfies all the required conditions. Total 7 person were there

$$\ \ \frac{\ 5\times\ 5\times\ 5}{6\times6\ \times6\ \ }=\ \frac{\ 125}{216}$$Let the player bet Re 1 on any particular number.

If exactly 1 die shows the number, the player will get Rs 2. (Operator has to lose Re 1 from his side). Probability of it is $$\ \frac{\ 1\times\ 5\times\ 5\times\ 3}{6\times\ 6\times\ 6}=\ \ \frac{\ 75}{216}$$

If exactly 2 die shows the number, the player will get Rs 3. (Operator has to lose Rs 2 from his side). Probability of it is $$\ \frac{\ 1\times\ 1\times\ 5\times\ 3}{6\times\ 6\times\ 6}=\ \frac{\ 15}{216}$$

If all die shows the number, the player will get Rs 4. (Operator has to lose Rs 3 from his side). Probability of it is $$\ \ \frac{\ 1\times\ 1\times\ 1}{6\times6\ \times6\ \ }=\ \frac{\ 1}{216}$$

If no die shows the number, the player will get Rs 0. (Operator will gain Re 1). Probability of it is $$\ \ \frac{\ 5\times\ 5\times\ 5}{6\times6\ \times6\ \ }=\ \frac{\ 125}{216}$$

Overall expected earning of Operator will be = $$\left(-1\right)\times\ \ \frac{\ 75}{216}+\left(-2\right)\times\ \ \frac{\ 15}{216}+\left(-3\right)\times\ \ \frac{\ 1}{216}+\left(1\right)\ \frac{\ 125}{216}$$

Overall Earning Per rupee is $$\ \frac{\ 17}{216}=\ 0.078$$

His earning per rupee is 7.87%

Let $$y_i\ $$ represent the money Jaideep has when he enters the shop i.

Money spent by him = $$\frac{\ y_i}{2}+1\ $$ and money remaining withhim  is$$\frac{\ y_i}{2}-1\ $$

For 5th shop it is given that $$\frac{\ y_5}{2}-1\ =0\ $$ hence $$y_5$$ = 2. Therefore amount remaining with him after he exists Shop 4 is Rs 2

Which can be tabulated as

Hence  $$\frac{\ y_4}{2}-1\ $$ = 2 or $$y_4$$ = 6

Similarly $$y_1$$, $$y_2$$and$$y_3$$ can be calculated and the table gets filled as follows

Hence he got Rs 62 from his mother

The above statements can be represented in the following manner

a) All lawyers are wisemen - False

b) All wisemen are lawyers - False

c) Some extrovert are wisemen - True

d) All extrovert are lawyers - False

Option C is only correct

Let s,d and t represent the number of students who like only 1, only 2 and all 3 magazines.

Total Number of Student = s+d+t

s = $$40+60+110\ =\ 210$$

d = $$20+50+40\ =\ 110$$

t = 30

Hence total students = $$210+110+30=350$$

From the Venn Diagram, we can calculate that the no. of students who do not read Business India = 110 + 40 + 60 = 210

From the statements given in question, the above venn diagrams represents the results of the surveys conducted in 2006 and 2007.

From the venn diagam that represents the 2006 survey, we sum up all the groups of people to get total no. of students which is 350.

The same set of students were surveyed in 2007 and from the statements, we drew the venn diagram for 2007 survey. All 350 students read India Today and among them 120 read Outlook. So, the no. of students who read only India Today = 350-120 = 230

It is given, product of their ages is 36.
Possible combinations are:
1*1*36 - sum = 38
1*2*18- sum = 21
1*3*12 - sum = 16
1*4*9 - sum = 14
1*6*6 -sum = 13
2*2*9 - sum = 13
2*3*6 - sum = 11
3*3*4 - sum = 10
The census takers comes back and ask for more information implies that the sum is 13. There are two possibilities for only sum 13, as there are two possibilities census taker comes back and asks for other clue.
(1, 6, 6) or (2, 2, 9)
The woman says her oldest child is sleeping upstairs. Therefore, the ages will be (2, 2, 9).
The answer is option A.