PGDBA 2019

Instructions

Answer the questions based on the following information.
The following bar diagram represents the number of daily wages (in rupees) of 100 labourers in different wage classes on a construction site. Here the class interval a-b includes all wages (in rupees) greater than or equal to a and less than b except for the interval 360-400, where both the end points are included.

No.of labourers 

                                                   Wages in Rupees

Question 1

The number of labourers receiving at least 320 is:

Video Solution
Question 2

The number of labourers receiving less than Rs.250 is

Video Solution
Question 3

The maximum wage (in Rupees), such that at least 50% of the labourers definitely earn more than that, is

Video Solution
Instructions

Answer the questions based on the following information.
The following table gives month-wise arrivals of foreign tourists in India in the years 2016 & 2017.
Table: Month-wise Arrivals of Foreign Tourists (in Thousands) in India (2016-2017)


Question 4

In which month of 2017 is the percentage increase over the corresponding month of the previous year the minimum?

Video Solution
Question 5

In which month of 2017 is the percentage increase over the previous month the maximum?

Video Solution
Instructions

For the following questions answer them individually

Question 6

If $$ f(x) = \log_{e}({\frac{2 - x}{9 - x^2}})$$, then the domain of the function $$f$$ is

Video Solution
Question 7

If the system of linear equations
$$2x+ y+7z = a$$
$$6x-2y+11z = b$$
$$2x-y+3z = c$$ 
has infinite number of solutions, then $$a, b, c$$ must satisfy

Video Solution
Question 8

If $$\alpha, \beta$$ are the roots of the equation $$x^2 + 3x - 3$$ , then the value of $$(\alpha + 1)^{-1} + (\beta +1)^{-1}$$ is equal to

Video Solution
Question 9

The number of real roots of the equation 

$$(e^x + e^{-x})^3 + 3(e^x + e^{-x})^2 + 3(e^x + e^{-x}) = 7$$

Video Solution
Question 10

Let $$x = -\frac{1}{1!}\cdot\frac{3}{4} + \frac{1}{2!}\cdot(\frac{3}{4})^2 -\frac{1}{3!}\cdot(\frac{3}{4})^3 +$$.... and $$y = x - \frac{x^2}{2} + \frac{x^3}{3} - $$..... then the value of y is

Video Solution

Register with

OR
cracku

Boost your Prep!

Download App