MAH MBA CET Sample Paper 2025

The area of square = 10*10 = 100$$cm^2$$
Now the side of the square is equal to the diameter of the square.
Hence the diameter of the circle is 10cm
So the radius of the circle will be 5 cm.
Hence the area of the circle = $$\pi*r^2$$ = $$\pi*5^2$$ = 78.5$$cm^2$$
Thus, the remaining area = 100 - 78.5 = 21.5 $$cm^2$$

1321 = 29 x 45 + 16
Since 16 is the remainder when 29 divides 1321, 29-16 = 13 should be added to 1321 to make it divisible by 29.

$$10800 = 2^4 * 5^2 * 3^3$$

Number of divisors = (4+1) (2+1) (3 + 1) = 60

Quotient when 800 is divided by 24 is 33.
There are 33 numbers up to 800 divisible by 24

Unit digit in 476 x 198 x 359 x 242

= unit digit in 6 x 8 x 9 x 2 = 4

LCM of the fractions = (LCM of the numerator/ HCF of the denominator)
LCM of 3, 4 and 2 = 3*4 = 12
HCF of 7, 3, 9 = 1
Therefore, LCM of the given fractions = 12/1 = 12.

Let the required number be x.
When numbers 595, 853 and 486 is divided by x remainders are 3, 2 and 5 respectively.
So 595 - 3 = 592, 853 - 2 = 851 and 486 - 5 = 481 must be divisible by x
Greatest value of ‘x’ = HCF(592, 851, 481) = 37
Hence, option D is the right answer.

P will be in the form of LCM of n(4,5,6,8)+3
LCM of 4,5,6 and 8 is 120
Therefore required number is 120+3=123
When 123 is divided by 9 remainder is 6

Let the first term be "a" and the common difference of the AP be "d".

So, 14th terms of AP will be a+13d.

a+13d = 202 ----equation (1)

19th term of AP will be a+18d.

a+18d = 277    --------equation (2)

solving both equations, we get a = 7 and d = 15

Therefore, first term = 7

8th term = a+7d = 7+7*15 = 112

So, ratio = 7:112 = 1:16

Given that the first term of GP is 16 and sum till infinity is 24

So, $$S_∞=\dfrac{a}{1-r}$$, where $$a$$ is the first term and $$r$$ is the common ratio.

$$S_∞=\dfrac{16}{1-r}=48$$

$$1-r=\dfrac{16}{48}=\dfrac{1}{3}$$

or, $$r=\dfrac{2}{3}$$

Now, we have to find sum till infinity of another GP whose first term is 76 and common ratio is $$r_1=\left(r-\dfrac{1}{6}\right)=\dfrac{2}{3}-\dfrac{1}{6}=\dfrac{1}{2}$$

$$S_∞=\dfrac{76}{1-\dfrac{1}{2}}$$

$$S_∞=152$$

Hence, the answer is 152