MAH MBA CET Sample Paper 2026

We have the following table to fill according to the arrangement:

According to the statement 2, T attended the conference on Friday but not in New York and Q attended the conference in Paris

Further, statement 3 says that the person who attended the Tokyo conference did so on Wednesday.

Now, according to statement 4, S and Q attended the conference on consecutive days and none of them attended the conference on Tokyo. Therefore, none of them would have attended the conference on Wednesday. Hence, they attended the conference on Monday and Tuesday or they attended on Thursday and Friday.

However, T attended the conference on Thursday and Friday. Hence, S and Q must have attended the conference on Monday and Tuesday.

According to statement 1, P attended the conference in Sydney, he must have attended the conference on Thursday. Hence, R is left so he/she must have attended the conference on Wednesday in Tokyo.

Now, we are left with S and T to uniquely identify the locations. The remaining locations are London or New York so they must have attended at one of the location.

With this, we have the following table:

We will write down the direct information given above.

We are told that employee from sales team visits on Monday. And the employee from Network team visits on Friday.

We are also told that A didn't visit on Thursday. So, the only possible days that A would can visit Tuesday or Wednesday. Statement 4 says that Tech and sales Visited on consecutive days. So, the only possibitlity for Tech is Tuesday.

We are also told that tech and sales team visited on consecutive days. So, Tech team employee visited on Tuesday.

We are told that Teach and Design team didn't visit on consective days. So, Design team employee didn't visit on Wednesday. 

The only possibility for Design team employee will be thursday. Hence Marketing employee will be on Saturday.

Wednesday is the correct answer.

We will write down the direct information given above.

We are told that employee from sales team visits on Monday. And the employee from Network team visits on Friday.

We are also told that A didn't visit on Thursday. So, the only possible days that A would can visit Tuesday or Wednesday. Statement 4 says that Tech and sales Visited on consecutive days. So, the only possibitlity for Tech is Tuesday.

We are also told that tech and sales team visited on consecutive days. So, Tech team employee visited on Tuesday.

We are told that Teach and Design team didn't visit on consective days. So, Design team employee didn't visit on Wednesday. 

The only possibility for Design team employee will be thursday. Hence Marketing employee will be on Saturday.

We know that C didn't visit on Friday. So, C can't be from Networking. C is either from Sales or from Design.

Not the remaining two can be given to D and F in two ways.

So, 2*2 = 4 ways.

We will write down the direct information given above.

We are told that employee from sales team visits on Monday. And the employee from Network team visits on Friday.

We are also told that A didn't visit on Thursday. So, the only possible days that A would can visit Tuesday or Wednesday. Statement 4 says that Tech and sales Visited on consecutive days. So, the only possibitlity for Tech is Tuesday.

We are also told that tech and sales team visited on consecutive days. So, Tech team employee visited on Tuesday.

We are told that Teach and Design team didn't visit on consective days. So, Design team employee didn't visit on Wednesday. 

The only possibility for Design team employee will be thursday. Hence Marketing employee will be on Saturday.

We know that C didn't visit on Friday. So, C can't be from Networking. C is either from Sales or from Design.

We are told that F is from Sales. So, C will be from marketing. Hence, D will be from Networking.

We need to check for three options 

Option A: In 2021, there were 75+65=140 families in pink apartments, of which 15%, that is, 20 families, had less than 4 members. 

Looking at 2020, there were 68+62 = 130 families in pink apartments, of which 10%, that is, 13, had less than 4 members. Hence, 2021 is not our answer. 

Option B: In 2023, there were 175+175=150 families in pink apartments, of which 30%, that is, 45 families, had less than 4 members. 
Looking at 2022, there were 85 + 70 = 155 members in the pink apartment, of which 20%, that is, 21 families had less than 4 members; hence, this, too, is not our answer. 

Option C: In 2024, there were 78+62 = 140 families in pink apartments, 20 of which, that is 28 families, had less than 4 members. 
This is a decrease from 45 families in 2023

Of the given options, only 2024 had a lesser number of families with less than 4 members. 

Therefore, Option C is the correct answer.

In 2021, there were a total of 140 families in pink apartments. 

15% of these, that is, 21 families, had less than four members

10%, that is 14, had more than six members. 

we want to find the minimum number of people possible in the apartment 

We can assume that 21 families below the four-member mark have two members each, giving 42 people. 
The 14 families above the six-member mark have 7-seven members each, giving 98 people. 

And the remaining families: 140-21-14 = 105, had four members each, giving 420 people. 

The total number of family members would hence be: 420+92+48 = 560

Therefore, Option C is the correct answer. 

In 2018, there were a total of 65+55 = 120 members living in pink apartments in the year 2018

Of these, 12 families had less than four members. To maximize the number of people, we can take all these families and make them all have three members, giving 36 people. 

36 had more than 6 people; to maximize the number of people, we can take them all and make them each have eight members, giving 288 members. 

The remaining 72 families can have six members each, giving 432 members. 

This would give the total number of members in the society to be 756

Therefore, Option A is the correct answer. 

The average number of families in building A would be $$\frac{60+75+68+75+85+75+78}{7}=\frac{521}{7}$$

The average number of families sin building B would be $$\frac{55+65+62+65+70+75+62}{7}=\frac{454}{7}=$$

The difference would be $$\frac{521-454}{7}=\frac{67}{7}\approx\ 9.5$$

Therefore, Option B is the correct answer. 

We know each friend obtained a different score in each round and each friend has a unique score in each round.

The scores are from 1 to 5.

Sum of 1 to 5 = 1+2+3+4+5 = 15

That means if we look at the total score of round 1 to round 4, the score not obtained in any round by any friend will be 15-total score.

For Abhay = 15-12 = 3 (Abhay didn't received a score of 3 in any round).

Similarly, for Bharat, Chandan, Deepak and Ganesh, the scores not obtained in any round are 4,5,2 and 1, respectively.

Now filling the table-

For Ganesh, total = 14

We know round 1+ round 2 = 9, so round 3+round 4 = 5 and scores will be 2 and 3.

Since Bharat has scored 2 in round 3, Ganesh will score 3 in round 3, thus he scores 2 in round 4.

Chandan has either received a score of 4 in round 1 or round 3. But, in round 1, Ganesh has scored 4, so Chandan scored 4 in round 3 and scored 1 in round 1.

In round 3, either Abhay or Deepak has scored 5.

So, option D.

We know each friend obtained a different score in each round and each friend has a unique score in each round.

The scores are from 1 to 5.

Sum of 1 to 5 = 1+2+3+4+5 = 15

That means if we look at the total score of round 1 to round 4, the score not obtained in any round by any friend will be 15-total score.

For Abhay = 15-12 = 3 (Abhay didn't received a score of 3 in any round).

Similarly, for Bharat, Chandan, Deepak and Ganesh, the scores not obtained in any round are 4,5,2 and 1, respectively.

Now filling the table-

For Ganesh, total = 14

We know round 1+ round 2 = 9, so round 3+round 4 = 5 and scores will be 2 and 3.

Since Bharat has scored 2 in round 3, Ganesh will score 3 in round 3, thus he scores 2 in round 4.

Chandan has either received a score of 4 in round 1 or round 3. But, in round 1, Ganesh has scored 4, so Chandan scored 4 in round 3 and scored 1 in round 1.

In round 4, someone has to score 4. Abhay, Chandan and Ganesh have already scored 4, and Bharat cannot score 4, so Deepak will score 4 in round 4.