MAH MBA CET Sample Paper 2026

Mapping the alphameric values, we can see that the numeric position of the alphabets give an average which is the same as the number between the two:

A+I= (1+9)/2 = 5

D+J = (4+10)/2 = 7

G+K = (7+11)/2 = 9

The next term in the series should also be following this pattern. 

Also looking at the series we can see that the numbers ae increasing by 2 each turn, the next term should have 11 in the middle. 

This narrows down options to C and E. 

Of the two options, D would give an average of (11+13)/2 = 12

Hence E is the most logical next term of the series.

Let's analyze the pattern:

• 2 = 1 × 2
• 6 = 2 × 3
• 12 = 3 × 4
• 20 = 4 × 5
• 30 = 5 × 6
• 42 = 6 × 7
• 56 = 7 × 8
• 74 ≠ 8 × 9
• 90 = 9 × 10

The pattern here is that each number is the product of two consecutive integers.

However, 74 does not follow the same pattern.

Hence, 74 is the odd one out.

The position of the letters in the alphabet corresponds to whether the numbers that follow are even or odd.
For letters in odd positions (A = 1, C = 3, E = 5, G = 7, I = 9), they are paired with odd numbers.
For letters in even positions (B = 2, D = 4, F = 6, H = 8, J = 10), they are paired with even numbers.

Option E: I (odd, 9) paired with 4 (even), J (even, 10) paired with 7 (odd) — Violates the pattern because the first letter (odd) is not paired with an odd number, the same goes for the second letter as well. 

We notice that the figure is in the 5th option:

9 % 5 m $ & f d 5 ) ! 8 # 7 p f 3 * d ? 1 m \ e 6 2 ! ? h

The 15th character from the left = p

The 27th character from the right = 5

So, the characters between them are 5 m $ & f d 5 ) ! 8 # 7 p

The character which is in the middle is 5

Sorting each word alphabetically:

House → ehosu; Tree → eert; Water → aertw; Friend → definr; Chair → achir; Phone → ehnop; Flower → eflorw

Move all vowels to the front (without changing their order):

House → eouhs; Tree → eert; Water → aertw; Friend → eidfnr; Chair → aichr; Phone → eohnp; Flower → eoflrw

aertw, aichr are the first two as they are starting with 'a'.

Among the words that start with 'e', tree will be ranked third.

So, tree is the answer.

Since the words would be flipped, we need to look at their ending rather than their start

We see that pad and broad would be the first two, in some order (starting with d)

The next word would be ending with e: Bottle, Mouse, Eliminate; since we want to find the fifth one, we will have to check for them. 

Bottle would be first, starting with l

Mouse would be second, starting with s
and finally, Eliminate would be third, starting with t

Therefore, Option D is the correct answer. 

If all the alphabets of the word " PROBABILITY " are replaced with the FOURTH next alphabet.

The new word formed is :

TVSFEFMPMXC.

Hence Q is not a part of the new word.

Option E is the correct answer.

SERENDIPITY arranged alphabetically becomes DEEIINPRSTY. 

Doing the operation that is described in the question we now get, F I I O O P Q S T V Z. 

We see that there are exactly 4 letters between and P and Z. 

Hence, the answer is 4.

The word given is LOQUACIOUS

Reverse alphabetical but vowels first, 
Vowels being: OUAIOU, in reverse order would be UUOOIA

Consonants being: LQCS in reverse order is SQLC

The needed string UUOOIASQLC

We see there are three letters between L and I