JEE Advanced 2026 Paper-2

Instructions

For the following questions answer them individually

JEE Advanced 2026 Paper-2 - Question 11


In a single slit diffraction experiment, a slit of width $$(0.016\pm 0.002)\,\mathrm{mm}$$ is used to measure the wavelength of a monochromatic light source. In the diffraction pattern, the angular distance between the central maximum and first minimum is measured to be $$(2^\circ\pm 40')$$. The value of the fractional error in the measurement of wavelength is:

[Given: $$\sin(2^\circ)=0.035$$]

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JEE Advanced 2026 Paper-2 - Question 12


As shown in the figure, a ray $$AB$$ of unpolarized light enters from water of refractive index $$n_w=4/3$$ into a medium of refractive index $$n_p=4/\sqrt{3}$$ after passing through a glass plate of refractive index $$n_g=1.5$$ and a layer of water. At a particular incident angle $$i$$ the reflected ray $$CD$$ is polarized in the direction as shown in the figure. The value of $$i$$ (in degrees) is:

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JEE Advanced 2026 Paper-2 - Question 13


As shown in the figure, the resistance of a galvanometer $$G$$ can be found by the half-deflection method. Here the resistance $$R_2$$ is adjusted such that when the key $$K$$ is closed the deflection in the galvanometer becomes half of the value as compared to when $$K$$ is open. Half-deflection is obtained at $$R_2=4\,\Omega$$ and thus the galvanometer resistance is found to be $$6\,\Omega$$. In this half-deflection condition the current (in mA) through the resistor $$R_1$$ is:

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JEE Advanced 2026 Paper-2 - Question 14


In a new system of units, the units of mass, length, time and current are $$5\,\mathrm{kg}$$, $$5\,\mathrm{m}$$, $$5\,\mathrm{s}$$ and $$5\,\mathrm{A}$$, respectively. If $$\mu_0$$ and $$\epsilon_0$$ are the permeability and permittivity of free space, respectively, then in this new system of units, the magnitude of one SI unit of $$\sqrt{\mu_0/\epsilon_0}$$, is:

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JEE Advanced 2026 Paper-2 - Question 15


Question Stem for Question Nos. 15 and 16

A container of height $$2\,\mathrm{m}$$, length $$2\,\mathrm{m}$$ and breadth $$1\,\mathrm{m}$$ is made of insulating vertical walls and two large area horizontal metal plates ($$M_1$$ and $$M_2$$) which extend far beyond the vertical walls in all directions. The container is partitioned into two equal chambers with a thin insulating vertical wall. The partition wall contains a small hole of cross-sectional area $$\sqrt{10}\,\mathrm{cm^2}$$ near its bottom edge. Initially the hole is closed and the left chamber of the container is completely filled with a liquid of dielectric constant $$\epsilon_r=15$$ and the right chamber is empty ($$\epsilon_r=1$$). At time $$t=0$$, the hole is opened and the liquid flows from the left chamber to the right chamber. In both the chambers, the space above the liquid has $$\epsilon_r=1$$ and is maintained at atmospheric pressure. The schematic of the container at a time $$t>0$$ is shown in the figure.

[Given: acceleration due to gravity is $$10\,\mathrm{ms^{-2}}$$.]

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The height (in m) of the liquid in left chamber at $$t=500\,\mathrm{s}$$ is:

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JEE Advanced 2026 Paper-2 - Question 16


Question Stem for Question Nos. 15 and 16

A container of height $$2\,\mathrm{m}$$, length $$2\,\mathrm{m}$$ and breadth $$1\,\mathrm{m}$$ is made of insulating vertical walls and two large area horizontal metal plates ($$M_1$$ and $$M_2$$) which extend far beyond the vertical walls in all directions. The container is partitioned into two equal chambers with a thin insulating vertical wall. The partition wall contains a small hole of cross-sectional area $$\sqrt{10}\,\mathrm{cm^2}$$ near its bottom edge. Initially the hole is closed and the left chamber of the container is completely filled with a liquid of dielectric constant $$\epsilon_r=15$$ and the right chamber is empty ($$\epsilon_r=1$$). At time $$t=0$$, the hole is opened and the liquid flows from the left chamber to the right chamber. In both the chambers, the space above the liquid has $$\epsilon_r=1$$ and is maintained at atmospheric pressure. The schematic of the container at a time $$t>0$$ is shown in the figure.

[Given: acceleration due to gravity is $$10\,\mathrm{ms^{-2}}$$.]

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The difference in the capacitance (in F) between the metal plates at $$t=0$$ and that at $$t=500\,\mathrm{s}$$ is $$(8-n)\epsilon_0$$, where $$\epsilon_0$$ is the permittivity of free space. The value of $$n$$ is:

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JEE Advanced 2026 Paper-2 - Question 17


Question Stem for Question Nos. 17 and 18

A uniform circular disk of radius $$0.2\,\mathrm{m}$$ and mass $$1\,\mathrm{kg}$$ is pivoted at its top point $$C$$ such that it can rotate freely around $$C$$ in the $$XY$$ plane, as shown in the figure. Initially, when the disk is at rest, a particle of mass $$20\,\mathrm{g}$$, travelling along negative $$x$$ direction in the $$XY$$ plane with speed $$100\,\mathrm{ms^{-1}}$$, hits the circumference of the disk at a point $$P$$. After collision the particle moves along negative $$y$$ direction at a speed of $$90\,\mathrm{ms^{-1}}$$.

[Given: the acceleration due to gravity $$(g)=-10\hat{j}\,\mathrm{ms^{-2}}$$]

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After the collision the disk starts to rotate around point $$C$$ in the $$XY$$ plane. The maximum change in the height (in m) of its center $$O$$ is:

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JEE Advanced 2026 Paper-2 - Question 18


Question Stem for Question Nos. 17 and 18

A uniform circular disk of radius $$0.2\,\mathrm{m}$$ and mass $$1\,\mathrm{kg}$$ is pivoted at its top point $$C$$ such that it can rotate freely around $$C$$ in the $$XY$$ plane, as shown in the figure. Initially, when the disk is at rest, a particle of mass $$20\,\mathrm{g}$$, travelling along negative $$x$$ direction in the $$XY$$ plane with speed $$100\,\mathrm{ms^{-1}}$$, hits the circumference of the disk at a point $$P$$. After collision the particle moves along negative $$y$$ direction at a speed of $$90\,\mathrm{ms^{-1}}$$.

[Given: the acceleration due to gravity $$(g)=-10\hat{j}\,\mathrm{ms^{-2}}$$]

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Amount of energy loss (in J) in the collision is:

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JEE Advanced 2026 Paper-2 - Question 19


At 300 K, the molar conductivities of the aqueous solutions of three salts at two different concentrations are given below:

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The conductivity of a saturated aqueous solution of AgCl is $$1.40\times 10^{-6}$$ S cm$$^{-1}$$ at 300 K. If the solubility of AgCl in water at 300 K is $$X$$ mol L$$^{-1}$$, then $$\log_{10}(X^{-1})$$ is

(Assume that AgCl dissolved in water ionizes completely and that the molar conductivity of saturated AgCl solution is equal to its limiting molar conductivity.)

JEE Advanced 2026 Paper-2 - Question 20


The correct order of ONO bond angle in the given species is

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