JEE (Advanced) 2017 Paper-2
For the following questions answer them individually
Compounds P and R upon ozonolysis produce Q and S, respectively. The molecular formula of Q and S is $$C_{8}H_{8}O$$. Q undergoes Cannizzaro reaction but not haloform reaction, whereas S undergoes haloform reaction but not Cannizzaro reaction.
The option(s) with suitable combination of P and R, respectively, is(are)
Upon heating $$KClO_{3}$$ in the presence of catalytic amount of $$MnO_{2}$$ a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure $$HNO_{3}$$ gives Y and Z.
The reaction of compound P with $$CH_{3}MgBr$$ (excess) in $$(C_{2}H_{5})_{2}O$$ followed by addition of $$H_{2}O$$ gives Q. The compound Q on treatment with $$H_{2}SO_{4}$$ at $$0^{0}_{C}$$ gives R. The reaction of R with $$CH_{3}COCl$$ in the presence of anhydrous $$AlCl_{3}$$ in $$CH_{2}Cl_{2}$$ followed by treatment with $$H_{2}O$$ produces compound S. [Et in compound P is ethyl group]
For the following questions answer them individually
The equation of the plane passing through the point (1, 1, 1) and perpendicular to the planes $$2x+y-2z=5$$ and $$3x-6y-2z=7$$, is
Let O be the origin and let PQR be an arbitrary triangle. The point S is such that $$\overrightarrow{OP}.\overrightarrow{OQ}+\overrightarrow{OR}.\overrightarrow{OS}=\overrightarrow{OR}.\overrightarrow{OP}+\overrightarrow{OQ}.\overrightarrow{OS}=\overrightarrow{OQ}.\overrightarrow{OR}+\overrightarrow{OP}.\overrightarrow{OS}$$ Then the triangle PQR has S as its
If $$y=y(x)$$ ) satisfies the differential equation $$8\sqrt{x}(\sqrt{9+\sqrt{x}})dy=(\sqrt{4+\sqrt{9+\sqrt{x}}})^{-1}dx$$, x>0 and $$Y(0)=\sqrt{7}$$, then y(256)=
If $$f:R\rightarrow R$$is a twice differentiable function such that $$f''(x)>0$$ for all $$x\epsilon R$$, and $$f(\frac{1}{2})=\frac{1}{2},f(1)=1$$, then
