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If $$f:R\rightarrow R$$is a twice differentiable function such that $$f''(x)>0$$ for all $$x\epsilon R$$, and $$f(\frac{1}{2})=\frac{1}{2},f(1)=1$$, then
$$f'(1)\leq0$$
$$0<f'(1)\leq\frac{1}{2}$$
$$\frac{1}{2}<f'(1)\leq\ 1$$
$$f'(1)>1$$
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