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Three persons A, B and C together complete a work in 3 days; B and C together complete the work in 6 days; and A and C together complete the same work in $$4\frac{1}{2}$$ days. Then the number of days in which C alone can complete the work is
Let the total work be 18 units and the capacities of A,B,C be a,b,c units/day respectively.Β
Hence, a+b+c = 6 and b+c = 3Β ==> a = 3 units/dayΒ
Also, a + c = 4 hence, c = 1 unit/day.Β
Hence, time required by C alone to complete all the work = 18 days
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