CAT 2018 Question Paper (Slot 2) Question 90

Question 90

The smallest integer n for which $$4^{n} > 17^{19}$$ holds, is closest to

Solution

$$4^{n} > 17^{19}$$

$$\Rightarrow$$ $$16^{n/2} > 17^{19}$$

Therefore, we can say that n/2 > 19

n > 38

Hence, option D is the correct answer. 


View Video Solution

video

Create a FREE account and get:

  • All Quant CAT Formulas and shortcuts PDF
  • 30+ CAT previous papers with solutions PDF
  • Top 500 CAT Solved Questions for Free

Comments
cracku

Boost your Prep!

Download App