Question 89

If (4x -5) = (3x -1), then the numerical value of $$(x + 4)^{2}$$ is

Solution

Given : (4x - 5) = (3x -1)

=> $$4x - 3x = 5 - 1$$

=> $$x = 4$$

To find : $$(x + 4)^2$$

= $$(4 + 4)^2 = 8^2 = 64$$

=> Ans - (B)

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