Two cars travel from city A to city B at a speed of 60 and 108 km/hr respectively. If one car takes 2 hours lesser time than the other car for the journey, then the distance between City A and City B?

Let the distance between City A and City B = $$d$$ km

Speed of first car = 60 km/hr and speed of second car = 108 km/hr

Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 2)$$ hrs

Using, speed = distance/time for first car :

=> $$\frac{d}{t} = 60$$

=> $$d = 60t$$ --------------(i)

For second car, => $$\frac{d}{t - 2} = 108$$

Substituting value of $$d$$ from equation (i), we get :

=> $$60t = 108t - 216$$

=> $$108t - 60t = 48t = 216$$

=> $$t = \frac{216}{48} = 4.5$$ hrs

From equation (i), => $$d = 60 \times 4.5 = 270$$ km

=> Ans - (A)