The average marks of 56 students is shown as 60. It includes a wrong entry of 92 marks instead of 29 marks. The correct average is _____ .
Total marks of 56 students = 56 $$\times$$ 60 = 3360
Replacing 92 by 29 in the data, => Total marks = 3360 - 92 + 29 = 3297
=> Correct average = $$\frac{3297}{56} = 58.875$$
=> Ans - (A)
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