Question 78

40 men took a dip in a pool 30 m long and 25 m broad. If the average water displaced by a man is 5 m3, then what will be the rise (in cm) in level of the pool?

Solution

Let the rise in the pool = height of the pool = $$h$$ m

Water displaced by 40 men = $$40\times5=200$$ $$m^3$$

Thus, volume of pool = Volume of water displaced

=> $$30\times25\times h=200$$

=> $$h=\frac{20}{75}=\frac{4}{15}$$ m

=> $$h=\frac{4}{15}\times100$$ cm

=> $$h=26.67$$ cm

=> Ans - (B)

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