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Instructions
A thief, after committing the burglary, started fleeing at 12 noon, at a speed of 60 km/hr. He was then chased by a policeman X. X started the chase, 15 min after the thief had started, at a speed of 65 km/hr.
Solution
Time taken to catch the thief = $$\frac{d}{v}$$ (Where d is relative distance achieved in 15 min. = 15km. and v is relative velocity of poiliceman i.e. = 65-60 = 5 kmph)
So time taken = 3hr.
Hence he will catch thief at 3:15 pm
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