In $$\triangle$$ADC, E and B are the points on the sides AD and AC respectively such that $$\angle$$ABE = $$\angle$$ADC. If AE = 6 cm,BC = 2 cm, BE = 3 cm and CD = 5 cm, then (AB + DE)is equal to:

A

14 cm

B

16 cm

C

$$\frac{49}{3}$$ cm

D

$$\frac{46}{3}$$ cm