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In $$\triangle$$ADC, E and B are the points on the sides AD and AC respectively such that $$\angle$$ABE = $$\angle$$ADC. If AE = 6 cm,BC = 2 cm, BE = 3 cm and CD = 5 cm, then (AB + DE)is equal to:
14 cm
16 cm
$$\frac{49}{3}$$ cm
$$\frac{46}{3}$$ cm
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