Question 71
What is the ratio of the mean proportional between 4.8 and 10.8 and the third proportional to 0.4 and 2.4?
Solution
Mean proportional of 4.8 and 10.8 is -
$$x=\sqrt{(}4.8\times10.8)$$
$$x=\sqrt{(}51.84)$$
x = 7.2
Third proportional of 0.4 and 2.4 is -y
$$\frac{0.4}{2.4}=\frac{2.4}{y}$$
$$0.4y=2.4^2$$
$$y=\frac{5.76}{0.4}=14.4$$
Required ratio = $$x:y=7.2:14.4=1:2$$
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