Join WhatsApp Icon CAT WhatsApp Group
Question 71

What is the ratio of the mean proportional between 4.8 and 10.8 and the third proportional to 0.4 and 2.4?

Mean proportional of 4.8 and 10.8 is -

$$x=\sqrt{(}4.8\times10.8)$$

$$x=\sqrt{(}51.84)$$

x = 7.2

Third proportional of 0.4 and 2.4 is -y

$$\frac{0.4}{2.4}=\frac{2.4}{y}$$

$$0.4y=2.4^2$$

$$y=\frac{5.76}{0.4}=14.4$$

Required ratio = $$x:y=7.2:14.4=1:2$$

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free