Question 68

The value of $$1800\div20\times [(12-6)+(24-12)]$$ is:

Solution

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$$1800\div20\times [(12-6)+(24-12)]$$

= $$1800\div20\times [(6)+(12)]$$

= $$90\times [(6)+(12)]$$

= $$90\times 18$$ = 1620

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