Question 67

Triangle $$PDC$$ is drawn in side the square $$ABCD$$ of side 24 cm where $$P$$ lies on $$AB$$. What is the area of the triangle?

Solution

Area of the triangle = $$\frac{1}{2} \times base \times height$$

= $$\frac{1}{2} \times 24 \times 24$$ = 288 $$cm^2$$


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