Question 66

In the right triangle shown in the figure ,what is the value of $$\operatorname{cosec}\theta$$ ?

Solution

From the right angled triangle,

$$\operatorname{cosec}\theta=\frac{\text{Hypotenuse}}{\text{Opposite side}}=\frac{QR}{PQ}$$

$$\Rightarrow$$ $$\operatorname{cosec}\theta=\frac{13}{5}$$

Hence, the correct answer is Option A

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