Question 69

$$(3a-4b)^{3}$$ is equal to:

Solution

$$(3a-4b)^{3}$$

= $$(3a)^3 - (4b)^3 - 3(3a.4b)(3a-4b)$$

($$\because (a - b)^3 = a^3 - b^3 - 3ab(a - b)$$)

= $$27a^3 - 64b^3 - 36ab(3a-4b)$$

= $$27a^3 - 64b^3 - 108a^2b + 144ab^2$$

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