Solution
$$(3a-4b)^{3}$$
= $$(3a)^3 - (4b)^3 - 3(3a.4b)(3a-4b)$$
($$\because (a - b)^3 = a^3 - b^3 - 3ab(a - b)$$)
= $$27a^3 - 64b^3 - 36ab(3a-4b)$$
= $$27a^3 - 64b^3 - 108a^2b + 144ab^2$$
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