Question 64

If $$tan^2A - sin^2A = x$$, then value of x is

Solution

Expression : $$tan^2A - sin^2A = x$$

= $$\frac{sin^2 A}{cos^2 A} - sin^2 A$$

= $$sin^2 A (\frac{1}{cos^2 A} - 1)$$

= $$sin^2 A (\frac{1 - cos^2 A}{cos^2 A}) = sin^2 A (\frac{sin^2 A}{cos^2 A})$$

= $$tan^2 A sin^2 A$$

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