Question 62

An angle in a semicircle is

Solution

$$\angle$$ BOC = $$180^\circ$$

The angle subtended by an arc at the centre of the circle is double the angle subtended by it at any point on the circle.

=> $$\angle$$ BOC = $$2 \times \angle$$ BAC

=> $$\angle$$ BAC = $$\frac{180}{2}=90^\circ$$

=> Ans - (C)

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