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Question 61
A chord of length 16 cm is drawn in a circle of radius 10 cm. The distance of the chord from the centre of the circle is
Solution
Given : AB = 16 cm and OB = 10 cm
To find : OC = ?
Solution : The line from the centre of the circle to the chord bisects it at right angle.
=> AC = BC = $$\frac{1}{2}$$ AB
=> BC = $$\frac{16}{2}=8$$ cm
In $$\triangle$$ OBC,
=> $$(OC)^2=(OB)^2-(BC)^2$$
=> $$(OC)^2=(10)^2-(8)^2$$
=> $$(OC)^2=100-64=36$$
=> $$OC=\sqrt{36}=6$$ cm
=> Ans - (B)
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