Question 61
A chord of length 16 cm is drawn in a circle of radius 10 cm. The distance of the chord from the centre of the circle is
Solution
Given : AB = 16 cm and OB = 10 cm
To find : OC = ?
Solution : The line from the centre of the circle to the chord bisects it at right angle.
=> AC = BC = $$\frac{1}{2}$$ AB
=> BC = $$\frac{16}{2}=8$$ cm
In $$\triangle$$ OBC,
=> $$(OC)^2=(OB)^2-(BC)^2$$
=> $$(OC)^2=(10)^2-(8)^2$$
=> $$(OC)^2=100-64=36$$
=> $$OC=\sqrt{36}=6$$ cm
=> Ans - (B)
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
CAT Quant Questions | CAT Quantitative Ability
CAT Averages Mixtures Alligations QuestionsCAT Quadratic Equations QuestionsCAT Linear Equations QuestionsCAT Algebra QuestionsCAT Time, Distance and Work Questions
CAT DILR Questions | LRDI Questions For CAT
CAT Maxima-Minima QuestionsCAT Coins and Weights QuestionsCAT Quant Based DI QuestionsCAT Data change over a period QuestionsCAT Routes And Networks Questions
