Let A and B be two solid spheres such that the surface area of B is 300% higher than the surface area of A. The volume of A is found to be k% lower than the volume of B. The value of k must be
[CAT 2003 leaked]
Surface area of sphere A (of radius a) is $$4\pi*a^2$$
Surface area of sphere B (of radius b) is $$4\pi*b^2$$
=> $$4\pi*a^2$$/$$4\pi*b^2$$ = 1/4 => a:b = 1:2
Their volumes would be in the ratio 1:8
Therefore, k = 7/8 * 100% = 87.5%
Create a FREE account and get:
CAT Averages, Ratios & Proportions
CAT Logarithms, Surds & Indices
CAT Functions, Graphs & Statistics
CAT DI Data Change Over Period
CAT Tables With Missing Values
CAT LR Selections With Conditions
2 years, 6 months ago
IT IS GIVEN IN THE QUESTION ARE IS 300 PERCENT HIGHER..
WHERE DID U USE THAT?
ANSWER IS CORRECT BUT..