In an election, there were four candidates and 80% of the registered voters casted their votes. One of the candidates received 30% of the casted votes while the other three candidates received the remaining casted votes in the proportion 1 : 2 : 3. If the winner of the election received 2512 votes more than the candidate with the second highest votes, then the number of registered voters was
Let the number of registered votes be 100x
The number of votes casted = 80x
Votes received by one of the candidates = $$\frac{30}{100}\times80x$$ = 24x
Remaining votes = 80x - 24x = 56x
Votes received by other three candidates is $$\frac{56x}{6},\frac{2\times56x}{6},\ \frac{\ 3\times56x}{6}$$
It is given,
28x - 24x = 2512
4x = 2512
x = 628
The number of registered votes = 100x = 62800
The answer is option D.
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