Question 56

If $$3A=4B=5C$$, then $$A:B:C$$ is equal to:

Solution

$$3A=4B=5C$$

let the $$3A=4B=5C = k$$

A = k/3

B = K/4

C = K/5

A : B : C = $$\frac{k}{3} : \frac{k}{4} : \frac{k}{5}$$ = 20 : 15 : 12

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