What is the area of a sector of a circle of radius 14 cm and central angle $$45^{0}$$ ? (Take $$\pi=\frac{22}{7}$$)
Area of a sector of a circle = $$\pi r^2 \times \frac{central angle}{360}$$
Central angle =Â $$45^{0}$$
r = 14 cm
Area of a sector of a circle = $$ \frac{22}{7} \times (14)^2 \times \frac{45}{360}$$ =Â $$ \frac{22}{7} \times 196 \times \frac{45}{360}$$
= $$77 cm^2$$
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